pcm_encode.m
来自「北邮《通信原理基于Matlab的计算机仿真》书的源码 m文件 好不容易弄来的」· M 代码 · 共 53 行
M
53 行
function [out]=pcm_encode(x)
%x encode to pcm code
n=length(x);
%-4096<x<4096
for i=1:n
if x(i)>0
out(i,1)=1;
else
out(i,1)=0;
end
if abs(x(i))>=0 & abs(x(i))<32
out(i,2)=0;out(i,3)=0;out(i,4)=0;step=2;st=0;
elseif 32<=abs(x(i)) & abs(x(i))<64
out(i,2)=0;out(i,3)=0;out(i,4)=1;step=2;st=32;
elseif 64<=abs(x(i)) & abs(x(i))<128
out(i,2)=0;out(i,3)=1;out(i,4)=0;step=4;st=64;
elseif 128<=abs(x(i)) & abs(x(i)) <256
out(i,2)=0;out(i,3)=1;out(i,4)=1;step=8;st=128;
elseif 256<=abs(x(i)) & abs(x(i))<512
out(i,2)=1;out(i,3)=0;out(i,4)=0;step=16;st=256;
elseif 512<=abs(x(i)) & abs(x(i))<1024
out(i,2)=1;out(i,3)=0;out(i,4)=1;step=32;st=512;
elseif 1024<=abs(x(i)) & abs(x(i))<2048
out(i,2)=1;out(i,3)=1;out(i,4)=0;step=64;st=1024;
elseif 2048<=abs(x(i)) & abs(x(i))<4096
out(i,2)=1;out(i,3)=1;out(i,4)=1;step=128;st=2048;
else
fprintf('input overflow');
out(i,2)=1;out(i,3)=1;out(i,4)=1;step=128;st=2048;
end
if(abs(x(i))>=4096)
out(i,2:8) = [1 1 1 1 1 1 1];
else
tmp = floor( (abs(x(i))-st)/step );
t = dec2bin(tmp,4) - 48; %函数dec2bin输出的是ASCII字符串,48对应0
out(i,5:8) =t(1:4);
end
% out(i,5) = tmp
% out(i,5)= tmp>=(st+h0*st/2);
% h1=2*out(i,5)-1;
% out(i,6)= tmp>=(st+h0*st/2+h1*st/4);
% h2=2*out(i,6)-1;
% out(i,7)= tmp>=(st+h0*st/2+h1*st/4+h2*st/8);
% h3=2*out(i,7)-1;
% out(i,8)= tmp>=(st+h0*st/2+h1*st/4+h2*st/8+h3*st/16);
end
out=reshape(out',1,8*n);
⌨️ 快捷键说明
复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?