word.pas
来自「背包问题专项训练 动态规划算法 有题目的C++解法」· PAS 代码 · 共 25 行
PAS
25 行
program word(input, output);
var s : string;
w : array [1..100] of string;
st : array [0..100] of integer;
n, i, j : integer;
begin
assign(input, 'word.in'); reset(input);
readln(s);
readln(n);
for i := 1 to n do
readln(w[i]);
close(input);
fillchar(st, sizeof(st), $7F);
st[0] := 0;
for i := 1 to length(s) do
for j := 1 to n do
if (length(w[j]) <= i) and (st[i - length(w[j])] < st[i])
and (copy(s, i - length(w[j]) + 1, length(w[j])) = w[j])
then st[i] := st[i - length(w[j])] + 1;
writeln(st[length(s)])
end.
⌨️ 快捷键说明
复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?