2186.cpp

这是哈尔滨工业大学acmOJ的源代码

/*  This Code is Submitted by wywcgs for Problem 2186 on 2006-04-15 at 21:08:42 */ 
#include <cstdio>

const int DAY = 86400;
const double T = DAY*1.0 / 22;

int main()
{
	int angle, h, m, s;
	
	while(scanf("%d %d:%d:%d", &angle, &h, &m, &s) != EOF && angle >= 0) {
		int now = h*3600 + m*60 + s;
		double b = 120.0 * angle / 11;
		while(b < now) b += T;
		int next = (int)(b+1e-3) % DAY;
		printf("%02d:%02d:%02d\n", next/3600, next/60%60, next%60);
	}

	return 0;
}