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📄 2022.cpp

📁 这是哈尔滨工业大学acmOJ的源代码
💻 CPP
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/*  This Code is Submitted by wywcgs for Problem 2022 on 2005-10-01 at 08:04:32 */ 
#include <stdio.h>

int main()
{
	char s[9][128] = {"23 * 89 = 2047 = ( 2 ^ 11 ) - 1", 
					   "47 * 178481 = 8388607 = ( 2 ^ 23 ) - 1", 
					   "233 * 1103 * 2089 = 536870911 = ( 2 ^ 29 ) - 1",
					   "223 * 616318177 = 137438953471 = ( 2 ^ 37 ) - 1", 
					   "13367 * 164511353 = 2199023255551 = ( 2 ^ 41 ) - 1",
					   "431 * 9719 * 2099863 = 8796093022207 = ( 2 ^ 43 ) - 1",
					   "2351 * 4513 * 13264529 = 140737488355327 = ( 2 ^ 47 ) - 1", 
					   "6361 * 69431 * 20394401 = 9007199254740991 = ( 2 ^ 53 ) - 1", 
					   "179951 * 3203431780337 = 576460752303423487 = ( 2 ^ 59 ) - 1"};
	int n;
	while(scanf("%d", &n) == 1) {
		if(n >= 11) {
			printf("%s\n", s[0]);
		}
		if(n >= 23) {
			printf("%s\n", s[1]);
		}
		if(n >= 29) {
			printf("%s\n", s[2]);
		}
		if(n >= 37) {
			printf("%s\n", s[3]);
		}
		if(n >= 41) {
			printf("%s\n", s[4]);
		}
		if(n >= 43) {
			printf("%s\n", s[5]);
		}
		if(n >= 47) {
			printf("%s\n", s[6]);
		}
		if(n >= 53) {
			printf("%s\n", s[7]);
		}
		if(n >= 59) {
			printf("%s\n", s[8]);
		}
	}
	
	return 0;
}

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