1387.cpp

来自「这是哈尔滨工业大学acmOJ的源代码」· C++ 代码 · 共 16 行

/*  This Code is Submitted by wywcgs for Problem 1387 on 2005-12-27 at 14:23:14 */ 
#include <cstdio>
#include <cmath>

int main()
{
	int a, b, s, m, n;
	
	while(scanf("%d %d %d %d %d", &a, &b, &s, &m, &n) != EOF && a != 0) {
		double h = m * a, v = n * b;
		printf("%.2lf %.2lf\n", 90-atan(h/v)*180/M_PI, sqrt(h*h+v*v)/s);
	}
	
	return 0;
}