2127.cpp

来自「这是哈尔滨工业大学acmOJ的源代码」· C++ 代码 · 共 22 行

/*  This Code is Submitted by wywcgs for Problem 2127 on 2005-10-21 at 13:11:00 */ 
#include <cstdio>
#include <cmath>

int main()
{
	double D, d, s;
	double r, t, o;
	int n, i;
	
	scanf("%d", &n);
	for(i = 0; i < n; i++) {
		scanf("%lf %lf %lf", &D, &d, &s);
		t = (d + s) / 2;
		r = (D - d) / 2;
		o = 2 * asin(t / r);
		printf("%ld\n", (long)(2*M_PI/o));
	}
	
	return 0;
}