1055.cpp
来自「这是哈尔滨工业大学acmOJ的源代码」· C++ 代码 · 共 26 行
CPP
26 行
/* This Code is Submitted by wywcgs for Problem 1055 on 2006-02-12 at 02:46:11 */
#include <cstdio>
const int C_MAX = 128;
const int N_MAX = 1024;
int main()
{
double remain[N_MAX][C_MAX];
int i, j, c, n, m;
while(scanf("%d %d %d", &c, &n, &m) == 3 && c != 0) {
if(m > c || m > n || (m+n)%2 != 0) { printf("0.000\n"); continue; }
if(n > 1000) n = 1000 + (n&1);
remain[0][0] = 1;
for(i = 1; i <= n; i++)
for(j = i&1; j <= c; j += 2) {
remain[i][j] = remain[i-1][j+1]*(j+1.0)/c;
if(j != 0) remain[i][j] += remain[i-1][j-1]*(c-j+1.0)/c;
}
printf("%.3lf\n", remain[n][m]);
}
return 0;
}
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