1945.cpp

来自「这是哈尔滨工业大学acmOJ的源代码」· C++ 代码 · 共 22 行

/*  This Code is Submitted by wywcgs for Problem 1945 on 2005-09-26 at 11:51:45 */ 
#include <stdio.h>

int main()
{
	int M, N;
	
	while(scanf("%d %d", &M, &N) == 2) {
		if(N == 1) {
			printf("%d\n", ((M + 1) / 2));
		} else if(M == 1) {
			printf("%d\n", ((N + 1) / 2));
		} else if(M % 3 == 0 || N % 3 == 0) {
			printf("2\n");
		} else {
			printf("1\n");
		}
	}
	
	return 0;
}