2181.cpp
来自「这是哈尔滨工业大学acmOJ的源代码」· C++ 代码 · 共 24 行
CPP
24 行
/* This Code is Submitted by wywcgs for Problem 2181 on 2006-03-27 at 11:13:37 */
#include <cstdio>
#include <cstring>
const int L = 64;
const int NON = 128;
int main()
{
char unit[L], name[L], lack[NON][L];
int i, n = 0;
double a, r;
while(scanf("%lf %s %lf%*c", &a, unit, &r) != EOF && a >= 0) {
gets(name);
if(a*100 < r) strcpy(lack[n++], name);
else printf("%s %.1lf %s %.0lf%%\n", name, a, unit, 100*a/r);
}
printf("Provides no significant amount of:\n");
for(i = 0; i < n; i++) printf("%s\n", lack[i]);
return 0;
}
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