📄 2214.cpp
字号:
/* This Code is Submitted by wywcgs for Problem 2214 on 2006-04-26 at 12:22:30 */
#include <cstdio>
#include <algorithm>
using namespace std;
const int PN = 1024;
const int EN = 1 << 19;
int x[PN], y[PN];
class Edge {
public:
int mx, my, dx, dy;
void set(int, int);
bool operator <(const Edge&) const;
bool ce(const Edge&) const;
bool ke(const Edge&) const;
};
void Edge::set(int b, int e) {
mx = x[b]+x[e], my = y[b]+y[e];
dx = x[e]-x[b]; dy = y[e]-y[b];
if(dx < 0) dx = -dx, dy = -dy;
else if(dx == 0) dy = abs(dy);
}
bool Edge::operator <(const Edge& e) const {
if(mx != e.mx) return mx < e.mx;
else if(my != e.my) return my < e.my;
else return dy*e.dx < dx*e.dy;
}
bool Edge::ce(const Edge& e) const {
return mx == e.mx && my == e.my;
}
bool Edge::ke(const Edge& e) const {
return dy*e.dx == dx*e.dy;
}
Edge e[EN];
int main()
{
int t, T, i, j;
scanf("%d", &T);
for(t = 0; t < T; t++) {
int n; scanf("%d", &n);
for(i = 0; i < n; i++) scanf("%d %d", &x[i], &y[i]);
int en = 0;
for(i = 0; i < n; i++)
for(j = i+1; j < n; j++) e[en++].set(i, j);
sort(e, e+en);
int total = 0, ke = 0, kbe = 0;
for(i = 0; i <= en; i++, ke++)
if(i == 0 || i == en || !e[i].ce(e[i-1])) {
total += kbe*(ke-kbe);
ke = 0; kbe = 1;
} else if(e[i].ke(e[i-1])) kbe++;
else {
total += kbe*(ke-kbe);
kbe = 1;
}
printf("%d\n", total);
}
return 0;
}
⌨️ 快捷键说明
复制代码
Ctrl + C
搜索代码
Ctrl + F
全屏模式
F11
切换主题
Ctrl + Shift + D
显示快捷键
?
增大字号
Ctrl + =
减小字号
Ctrl + -