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📄 segmenttermvector.java

📁 lucene-2.4.0 是一个全文收索的工具包
💻 JAVA
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package org.apache.lucene.index;/** * Licensed to the Apache Software Foundation (ASF) under one or more * contributor license agreements.  See the NOTICE file distributed with * this work for additional information regarding copyright ownership. * The ASF licenses this file to You under the Apache License, Version 2.0 * (the "License"); you may not use this file except in compliance with * the License.  You may obtain a copy of the License at * *     http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */import java.util.*;class SegmentTermVector implements TermFreqVector {  private String field;  private String terms[];  private int termFreqs[];    SegmentTermVector(String field, String terms[], int termFreqs[]) {    this.field = field;    this.terms = terms;    this.termFreqs = termFreqs;  }  /**   *    * @return The number of the field this vector is associated with   */  public String getField() {    return field;  }  public String toString() {    StringBuffer sb = new StringBuffer();    sb.append('{');    sb.append(field).append(": ");    if(terms != null){      for (int i=0; i<terms.length; i++) {        if (i>0) sb.append(", ");        sb.append(terms[i]).append('/').append(termFreqs[i]);      }    }    sb.append('}');        return sb.toString();  }  public int size() {    return terms == null ? 0 : terms.length;  }  public String [] getTerms() {    return terms;  }  public int[] getTermFrequencies() {    return termFreqs;  }  public int indexOf(String termText) {    if(terms == null)      return -1;    int res = Arrays.binarySearch(terms, termText);    return res >= 0 ? res : -1;  }  public int[] indexesOf(String [] termNumbers, int start, int len) {    // TODO: there must be a more efficient way of doing this.    //       At least, we could advance the lower bound of the terms array    //       as we find valid indexes. Also, it might be possible to leverage    //       this even more by starting in the middle of the termNumbers array    //       and thus dividing the terms array maybe in half with each found index.    int res[] = new int[len];    for (int i=0; i < len; i++) {      res[i] = indexOf(termNumbers[start+ i]);    }    return res;  }}

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