e_atanh.c

来自「This is a resource based on j2me embedde」· C语言 代码 · 共 83 行

/*
 * @(#)e_atanh.c	1.12 06/10/10
 *
 * Copyright  1990-2008 Sun Microsystems, Inc. All Rights Reserved.  
 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER  
 *   
 * This program is free software; you can redistribute it and/or  
 * modify it under the terms of the GNU General Public License version  
 * 2 only, as published by the Free Software Foundation.   
 *   
 * This program is distributed in the hope that it will be useful, but  
 * WITHOUT ANY WARRANTY; without even the implied warranty of  
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU  
 * General Public License version 2 for more details (a copy is  
 * included at /legal/license.txt).   
 *   
 * You should have received a copy of the GNU General Public License  
 * version 2 along with this work; if not, write to the Free Software  
 * Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA  
 * 02110-1301 USA   
 *   
 * Please contact Sun Microsystems, Inc., 4150 Network Circle, Santa  
 * Clara, CA 95054 or visit www.sun.com if you need additional  
 * information or have any questions. 
 *
 */

/* __ieee754_atanh(x)
 * Method :
 *    1.Reduced x to positive by atanh(-x) = -atanh(x)
 *    2.For x>=0.5
 *                  1              2x                          x
 *	atanh(x) = --- * log(1 + -------) = 0.5 * log1p(2 * --------)
 *                  2             1 - x                      1 - x
 *
 * 	For x<0.5
 *	atanh(x) = 0.5*log1p(2x+2x*x/(1-x))
 *
 * Special cases:
 *	atanh(x) is NaN if |x| > 1 with signal;
 *	atanh(NaN) is that NaN with no signal;
 *	atanh(+-1) is +-INF with signal.
 *
 */

#include "fdlibm.h"

#ifdef __STDC__
static const double one = 1.0, huge = 1e300;
#else
static double one = 1.0, huge = 1e300;
#endif


static const double zero  = 0.0;

#ifdef __STDC__
	double __ieee754_atanh(double x)
#else
	double __ieee754_atanh(x)
	double x;
#endif
{
	double t;
	int hx,ix;
	unsigned lx;
	hx = __HI(x);		/* high word */
	lx = __LO(x);		/* low word */
	ix = hx&0x7fffffff;
	if ((ix|((lx|(-(int)lx))>>31))>0x3ff00000) /* |x|>1 */
	    return (x-x)/(x-x);
	if(ix==0x3ff00000)
	    return x/zero;
	if(ix<0x3e300000&&(huge+x)>zero) return x;	/* x<2**-28 */
	__HI(x) = ix;		/* x <- |x| */
	if(ix<0x3fe00000) {		/* x < 0.5 */
	    t = x+x;
	    t = 0.5*log1p(t+t*x/(one-x));
	} else
	    t = 0.5*log1p((x+x)/(one-x));
	if(hx>=0) return t; else return -t;
}