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ex5_14
Solution of system of Example 5.14 x=x1,y=x2
x =
exp(t)*C1+t*exp(t)
y =
-1/2*C1*exp(3*t)+1/2*exp(t)*C1+exp(3*t)*C2+(1/2*t*exp(3*t)+1/4*exp(3*t)-1/3*exp(2*t))*exp(-2*t)
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Solve system with initial conditions
x =
2*exp(t)+t*exp(t)
y =
5/4*exp(t)+1/2*t*exp(t)-1/3+1/12*exp(3*t)
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