📄 ber_gmsk_l_2_h_6.m
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%M=2,h=1/2,GMSK,N=512,g=[17,15],Ns=16,2倍采样,L=2,H with 6 taps
clc
clear
EbN0=[0:2:10];
ber(1,:)=[1.2417e-001 1.0609e-001 1.0216e-001 1.0079e-001 9.8821e-002];
ber(2,:)=[6.5414e-002 3.1298e-002 3.0112e-002 3.0073e-002 3.0064e-002];
ber(3,:)=[3.2535e-002 1.1637e-002 1.1270e-002 1.0536e-002 1.1054e-002];
ber(4,:)=[1.2047e-002 3.3552e-003 2.7301e-003 2.4919e-003 2.3601e-003];
ber(5,:)=[4.1504e-003 6.1471e-004 3.8524e-004 3.5254e-004 3.4293e-004];
ber(6,:)=[1.4975e-003 7.8231e-005 3.3983e-005 3.4691e-005 3.9293e-005];
ber2 = [5.4295e-002 1.6745e-002 4.5721e-003 1.6621e-003 2.7238e-004 1.8468e-005]; % after decoding stbc MMSE Eq.
semilogy(EbN0,ber(:,1),'k-o',EbN0,ber(:,2),'k-s',EbN0,ber(:,3),'k->',EbN0,ber(:,4),'k-p',EbN0,ber(:,5),'k-<',EbN0,ber2,'k-v','LineWidth',2);
grid
xlabel('Eb/N0(dB)');
ylabel('BER');
legend('1st Iter','2nd Iter','3rd Iter','4th Iter','5th Iter','ML');
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