📄 ber_gmsk_l_2_h.m
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%M=2,h=1/2,GMSK,N=512,g=[17,15],Ns=16,2倍采样,L=2,H with 4 and 6 taps, 5 iterations
clc
clear
EbN0=[0:2:10];
ber1 = [6.1395e-002 2.3032e-002 6.5224e-003 2.2080e-003 4.0615e-004 4.8469e-005]; % H with 4 taps
ber2 = [9.8821e-002 3.2064e-002 1.1054e-002 2.3601e-003 3.4293e-004 3.9293e-005]; % H with 6 taps
semilogy(EbN0,ber1,'k-o',EbN0,ber2,'k-s','LineWidth',2);
grid
xlabel('Eb/N0(dB)');
ylabel('BER');
legend('H has 4 taps','H has 6 taps');
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