📄 a_5.13.htm
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<title>5.13的解答</title>
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<center><font class="title2"><b>练习5.13</b></font></center><br>
<p>解答: </p>
<p>(a)</p>
<table align = center border = 1 width = "50%" cellspacing="0" cellpadding="5">
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<td width = "33%"><div align = center>产生式</div></td>
<td width = "33%"><div align = center>语义规则</div></td>
<td><div align = center>动作</div></td>
</tr>
<tr>
<td > $</td>
<td align="right" > abbb$ </td>
<td>初始</td>
</tr>
<tr>
<td > $M</td>
<td align="right" >abbb$ </td>
<td>规约 M -> ε</td>
</tr>
<tr>
<td > $MM</td>
<td align="right" >abbb$ </td>
<td>规约 M -> ε</td>
</tr>
<tr>
<td > $MMM</td>
<td align="right" >abbb$ </td>
<td>规约 M -> ε</td>
</tr>
<tr>
<td > $MMMa</td>
<td align="right" >bbb$ </td>
<td>移进</td>
</tr>
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<td > $MMML</td>
<td align="right" >bbb$ </td>
<td>规约 L -> a</td>
</tr>
<tr>
<td > $MMMLb</td>
<td align="right" >bb$ </td>
<td>移进</td>
</tr>
<tr>
<td > $MML</td>
<td align="right" >bb$ </td>
<td>规约 L -> MLb</td>
</tr>
<tr>
<td > $MMLb</td>
<td align="right" >b$ </td>
<td>移进</td>
</tr>
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<td > $ML</td>
<td align="right" >b$ </td>
<td>规约 L -> MLb</td>
</tr>
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<td > $MLb</td>
<td align="right" >$ </td>
<td>移进</td>
</tr>
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<td > $L</td>
<td align="right" >$ </td>
<td>规约 L -> MLb</td>
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<td > </td>
<td align="right" > </td>
<td>接受</td>
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<p>(b) 构造文法的LR(1)项目的识别文法活前缀的DFA:</p>
<p align=center><img src="a_5.13.gif" width="554" height="295"></p>
<p> 在I<sub>0</sub>项目集中,存在移进-规约冲突,因此,它不是LR(1)的。</p>
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