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📄 4.10.11(b).htm

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<title>4.11(b)的解答</title>
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<center><font class="title2"><b>练习4.11(b)</b></font></center><br>
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解:<br>
该文法的拓广文法G'为
<table align=center width=450 class="content">
<tr><td>(0) S' → S</td><td>(1) S → aSAB</td></tr>       
<tr><td>(2) S  → BA</td><td>(3) A → aA</td></tr>       
<tr><td>(4) A  → B</td><td>(5) B → b</td></tr>       
</table>    
其LR(0)项目集规范族和goto函数(识别活前缀的DFA)如下:<br>    
I<sub>0</sub> = {S'→·S, S→·aSAB, S→·BA, B→·b}<br>    
I<sub>1</sub> = {S'→S·}<br>    
I<sub>2</sub> = {B→b·}<br>    
I<sub>3</sub> = {S→a·SAB, S→·aSAB, S→·BA, B→·b}<br>    
I<sub>4</sub> = {S→B·A, A→·aA, A→·B, B→·b}<br>    
I<sub>5</sub> = {S→aS·AB, A→·aA, A→·B, B→·b}<br>    
I<sub>6 </sub> = {S→aSA·B, B→·b}<br>    
I<sub>7</sub> = {A→a·A, A→·aA, A→·B, B→·b}<br>    
I<sub>8</sub> = {A→B·}<br>    
I<sub>9</sub> = {S→BA·}<br>    
I<sub>10</sub> = {S→aSAB·}<br>    
I<sub>11</sub> = {A→aA·}<br>    
<center><img src="images/ex4.11b_1.gif"></center><br>    
求<b>FOLLOW</b>集:<br>    
&nbsp;&nbsp;&nbsp;&nbsp;<b>FOLLOW</b>(S')={$}<br>   
&nbsp;&nbsp;&nbsp;&nbsp;<b>FOLLOW</b>(S)={a,b,$}<br>   
&nbsp;&nbsp;&nbsp;&nbsp;<b>FOLLOW</b>(A)={a,b,$}<br>   
&nbsp;&nbsp;&nbsp;&nbsp;<b>FOLLOW</b>(B)={a,b,$}<br>   
<center><img src="images/ex4.11b_2.gif" width="553" height="316"></center><br>   
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