9.5.3_e2.htm
来自「建立《编译原理网络课程》的目的不仅使学生掌握构造编译程序的原理和技术」· HTM 代码 · 共 41 行
HTM
41 行
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<img border="0" src="images/9_25_2.gif" align = left width="346" height="130">在图2(b)中的串联语句的规则有点微妙,由语句S=S1;S2产生的定值集合是什么?<p>
解析:首先,如果定值d由S2产生,那么它肯定由S产生;另外,如果d由S1产生,只要它不被S2注销,它也将到达S的结束点。所以我们认为: </p>
<p><span style="FONT-SIZE: large">gen[S]= gen[S2]∪(gen[S1]-kill[S2])</span></p>
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