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📄 蚁群算法 c语言程序(已运行)_元朋2007.mht

📁 几个蚁群算法源代码打包
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<DIV class=3Dtit>=D2=CF=C8=BA=CB=E3=B7=A8 =
C=D3=EF=D1=D4=B3=CC=D0=F2=A3=A8=D2=D1=D4=CB=D0=D0=A3=A9</DIV>
<DIV class=3Ddate>2008-04-19 21:10</DIV>
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      <DIV class=3Dcnt id=3Dblog_text>
      <P class=3DMsoNormal style=3D"MARGIN: 0cm 0cm 0pt"><SPAN=20
      style=3D"mso-bidi-font-size: 10.5pt"><FONT=20
      face=3D"Times New Roman">//</FONT></SPAN><SPAN=20
      style=3D"mso-hansi-: =
10.5pt">=B6=CE=BA=A3=B1=F5=BD=CC=CA=DA=D6=F7=B1=E0=B5=C4=A1=B6=D2=CF=C8=BA=
=CB=E3=B7=A8=D4=AD=C0=ED=BC=B0=C6=E4=D3=A6=D3=C3=A1=B7=B8=BD=C2=BC=C0=EF=B5=
=C4</SPAN><SPAN=20
      style=3D"mso-bidi-font-size: 10.5pt"><FONT=20
      face=3D"Times New Roman">C</FONT></SPAN><SPAN=20
      style=3D"mso-hansi-: 10.5pt">=B3=CC=D0=F2=B4=FA=C2=EB</SPAN><SPAN=20
      style=3D"mso-bidi-font-size: 10.5pt"><FONT face=3D"Times New =
Roman">.=20
      =B2=A2=D3=D0=BC=B8=CE=BB=CD=F8=D3=D1=D0=DE=B8=C4=A1=A3<BR>//Basic =
Ant Colony Algorithm for TSP <BR>#include=20
      &lt;iostream.h&gt; <BR>#include &lt;fstream.h&gt; <BR>#include=20
      &lt;math.h&gt; <BR>#include &lt;time.h&gt; <BR>#include =
&lt;conio.h&gt;=20
      <BR>#include &lt;stdlib.h&gt; <BR>#include &lt;iomanip.h&gt;=20
      <BR><BR>#define N 31 //city size <BR>#define M 31 //ant number=20
      <BR><BR>double inittao=3D1; <BR>double tao[N][N]; <BR>double =
detatao[N][N];=20
      <BR>double distance[N][N]; <BR>double yita[N][N]; <BR>int =
tabu[M][N];=20
      <BR>int route[M][N]; <BR>double solution[M]; <BR>int BestRoute[N]; =

      <BR>double BestSolution=3D10000000000; <BR>double alfa,beta,rou,Q; =
<BR>int=20
      NcMax; <BR>void initparameter(void); // initialize the parameters =
of basic=20
      ACA <BR>double EvalueSolution(int *a); // evaluate the solution of =
TSP,=20
      and calculate the length of path <BR>void InCityXY( double x[], =
double=20
      y[], char *infile ); // input the nodes' coordinates of TSP =
<BR><BR>void=20
      initparameter(void) <BR>{ <BR><SPAN style=3D"COLOR: red">alfa=3D1; =
beta=3D5;=20
      rou=3D0.9; Q=3D100; </SPAN><BR>NcMax=3D200; <BR>} <BR><BR>void =
main(void) <BR>{=20
      <BR>int NC=3D0; <BR>initparameter(); <BR>double x[N]; <BR>double =
y[N];=20
      <BR>InCityXY( x, y, "city31.tsp" ); <BR><BR>for(int =
i=3D0;i&lt;N;i++)=20
      <BR>for(int j=3Di+1;j&lt;N;j++) <BR>{=20
      =
<BR>distance[j][i]=3Dsqrt((x[i]-x[j])*(x[i]-x[j])+(y[i]-y[j])*(y[i]-y[j])=
);=20
      <BR>distance[i][j]=3Ddistance[j][i]; <BR>} <BR>// calculate the =
heuristic=20
      parameters <BR>for(i=3D0;i&lt;N;i++) <BR>for(int j=3D0;j&lt;N;j++) =
<BR>{=20
      <BR>tao[i][j]=3Dinittao; <BR>if(j!=3Di) =
<BR>yita[i][j]=3D100/distance[i][j];=20
      <BR>} <BR>for(int k=3D0;k&lt;M;k++) <BR>for(i=3D0;i&lt;N;i++)=20
      <BR>route[k][i]=3D-1; <BR>srand(time(NULL)); =
<BR>for(k=3D0;k&lt;M;k++) <BR>{=20
      <BR>route[k][0]=3Dk%N; <BR>tabu[k][route[k][0]]=3D1; <BR>} =
<BR>//each ant try=20
      to find the optiamal path <BR>do { <BR>int s=3D1; <BR>double =
partsum;=20
      <BR>double pper; <BR>double drand; <BR>//ant choose one whole path =

      <BR>while(s&lt;N) <BR>{ <BR>for(k=3D0;k&lt;M;k++) <BR>{ <BR>int=20
      jrand=3Drand()%3000; <BR>drand=3Djrand/3001.; <BR>partsum=3D0; =
<BR>pper=3D0;=20
      <BR>for(int j=3D0;j&lt;N;j++) <BR>{ <BR>if(tabu[k][j]=3D=3D0)=20
      =
<BR>partsum+=3Dpow(tao[route[k][s-1]][j],alfa)*pow(yita[route[k][s-1]][j]=
,beta);=20
      <BR>} <BR>for(j=3D0;j&lt;N;j++) <BR>{ <BR>if(tabu[k][j]=3D=3D0)=20
      =
<BR>pper+=3Dpow(tao[route[k][s-1]][j],alfa)*pow(yita[route[k][s-1]][j],be=
ta)/partsum;=20
      <BR>if(pper&gt;drand) <BR>break; <BR>} <BR>tabu[k][j]=3D1;=20
      <BR>route[k][s]=3Dj; <BR>} <BR>s++; <BR>} <BR>// the pheromone is =
updated=20
      <BR>for(i=3D0;i&lt;N;i++) <BR>for(int j=3D0;j&lt;N;j++) =
<BR>detatao[i][j]=3D0;=20
      <BR>for(k=3D0;k&lt;M;k++) <BR>{ =
<BR>solution[k]=3DEvalueSolution(route[k]);=20
      <BR>if(solution[k]&lt;BestSolution) <BR>{ =
<BR>BestSolution=3Dsolution[k];=20
      <BR>for(s=3D0;s&lt;N;s++) <BR>BestRoute[s]=3Droute[k][s]; <BR>} =
<BR>}=20
      <BR>for(k=3D0;k&lt;M;k++) <BR>{ <BR>for(s=3D0;s&lt;N-1;s++)=20
      <BR>detatao[route[k][s]][route[k][s+1]]+=3DQ/solution[k];=20
      <BR>detatao[route[k][N-1]][route[k][0]]+=3DQ/solution[k]; <BR>}=20
      <BR>for(i=3D0;i&lt;N;i++) <BR>for(int j=3D0;j&lt;N;j++) <BR>{=20
      <BR>tao[i][j]=3Drou*tao[i][j]+detatao[i][j]; =
<BR>if(tao[i][j]&lt;0.00001)=20
      <BR>tao[i][j]=3D0.00001; <BR>if(tao[i][j]&gt;20) =
<BR>tao[i][j]=3D20; <BR>}=20
      <BR>for(k=3D0;k&lt;M;k++) <BR>for(int j=3D1;j&lt;N;j++) <BR>{=20
      <BR>tabu[k][route[k][j]]=3D0; <BR>route[k][j]=3D-1; <BR>} =
<BR>NC++; <BR>}=20
      while(NC&lt;NcMax); <BR>//output the calculating results =
<BR>fstream=20
      result; <BR>result.open("optimal_results.log", ios::app); =
<BR>if(!result)=20
      <BR>{ <BR>cout&lt;&lt;"can't open the &lt;optimal_results.log&gt;=20
      file!\n"; <BR>exit(0); <BR>}=20
      =
<BR>result&lt;&lt;"*-----------------------------------------------------=
--------------------*"&lt;&lt;endl;=20
      <BR>result&lt;&lt;"the initialized parameters of ACA are as=20
      follows:"&lt;&lt;endl; =
<BR>result&lt;&lt;"alfa=3D"&lt;&lt;alfa&lt;&lt;",=20
      beta=3D"&lt;&lt;beta&lt;&lt;", rou=3D"&lt;&lt;rou&lt;&lt;",=20
      Q=3D"&lt;&lt;Q&lt;&lt;endl; <BR>result&lt;&lt;"the maximum =
iteration number=20
      of ACA is:"&lt;&lt;NcMax&lt;&lt;endl; <BR>result&lt;&lt;"the =
shortest=20
      length of the path is:"&lt;&lt;BestSolution&lt;&lt;endl;=20
      <BR>result&lt;&lt;"the best route is:"&lt;&lt;endl;=20
      <BR>for(i=3D0;i&lt;N;i++) <BR>result&lt;&lt;BestRoute[i]&lt;&lt;" =
";=20
      <BR>result&lt;&lt;endl;=20
      =
<BR>result&lt;&lt;"*-----------------------------------------------------=
--------------------*"&lt;&lt;endl&lt;&lt;endl;=20
      <BR>result.close(); <BR>cout&lt;&lt;"the shortest length of the =
path=20
      is:"&lt;&lt;BestSolution&lt;&lt;endl; <BR>} <BR><BR><BR><SPAN=20
      style=3D"COLOR: red">double EvalueSolution(int *a) </SPAN><BR>{ =
<BR>double=20
      dist=3D0; <BR>for(int i=3D0;i&lt;N-1;i++) =
<BR>dist+=3Ddistance[a[i]][a[i+1]];=20
      <BR>dist+=3Ddistance[a[i]][a[0]]; <BR>return dist; <BR>} =
<BR><BR><BR>void=20
      InCityXY( double x[], double y[], char *infile ) <BR>{ <BR>fstream =

      inxyfile( infile, ios::in | ios::nocreate ); <BR>if( !inxyfile ) =
<BR>{=20
      <BR>cout&lt;&lt;"can't open the &lt;"&lt;&lt;infile&lt;&lt;"&gt; =
file!\n";=20
      <BR>exit(0); <BR>} <BR>int i=3D0; <BR>while( !inxyfile.eof() ) =
<BR>{=20
      <BR>inxyfile&gt;&gt;x[i]&gt;&gt;y[i]; <BR>if( ++i &gt;=3D N ) =
break; <BR>}=20
      <BR>} </FONT></SPAN></P>
      <P class=3DMsoNormal style=3D"MARGIN: 0cm 0cm 0pt"><SPAN=20
      style=3D"mso-bidi-font-size: 10.5pt"><FONT=20
      face=3D"Times New =
Roman">=C1=ED=CD=E2=A3=BA=C4=E3=D0=E8=D2=AA=BD=A8=C1=A2=D2=BB=B8=F6=C3=FB=
=CE=AAcity31.tsp=B5=C4=CE=C4=BC=FE=A3=AC=B4=E6=B7=C531=B8=F6=B3=C7=CA=D0=B5=
=C4=D7=F8=B1=EA=A1=A3</FONT></SPAN></P></DIV></TD></TR></TBODY></TABLE><B=
R>
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