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📄 gauss_jordan.f90

📁 用FORTRAN 编写的高斯约旦法解方程的程序
💻 F90
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module LinearAlgebra
    implicit none
contains

!Gauss_Jordan method
subroutine Gauss_Jordan(A,S,ANS)
    implicit none
	real :: A(:,:)
	real :: S(:)
	real :: ANS(:)
	real,allocatable :: B(:,:)
	integer :: i,N
	N=size(A,1)
	allocate(B(N,N))
	! 保存原先的矩阵数组A以及数组S
	B=A
	ANS=S
	!把B化成对角线矩阵(除了对角线以外全是0)
	call Upper(B,ANS,N) !先把B化成上三角矩阵
	call Lower(B,ANS,N) !再把B化成下三角矩阵
	!求解
	forall(i=1:N)
	   ANS(i)=ANS(i)/B(i,i)
	end forall
	return
end subroutine Gauss_Jordan

!输出等式 
subroutine output(M,S)
   implicit none
   real :: M(:,:),S(:,:)
   integer :: N,i,j
   N=size(M,1)
   !write 中加上advance="no",可以终止断行的发生
   !write 接续在同一行中
   do i=1,N
      write(*,"(1x,f5.2,a1)",advance="NO")M(i,1),'A'
	  do j=2,N
	     if(M(i,j)<0)then
		   write(*,"('-',f5.2,a1)",advance="NO")-M(i,j),char(64+j)
		 else
		   write(*,"('+',f5.2,a1)",advance="NO")M(i,j),char(64+j)
		 endif
	  enddo
	  write(*,"('=',f8.4)")S(i)
   enddo
   return
end subroutine output

!求上三角矩阵的子程序
subroutine Upper(M,S,N)
   implicit none
   integer :: N
   real :: M(N,N)
   real :: S(N)
   integer :: I,J
   real :: E
   do I=1,N-1
     do J=I+1,N
	    E=M(J,I)/M(I,I)
		M(J,I:N)=M(J,I:N)-M(I,I:N)*E
		S(J)=S(J)-S(I)*E
	 enddo
   enddo
   return
end subroutine Upper

!求下三角矩阵的子程序
subroutine Lower(M,S,N)
   implicit none
   integer :: N
   real :: M(N,N)
   real :: S(N)
   integer :: I,J
   real :: E
   do I=N,2,-1
     do J=I-1,1,-1
	    E=M(J,I)/M(I,I)
		M(J,1:N)=M(J,1:N)-M(I,1:N)*E
		S(J)=S(J)-S(I)*E
	 enddo
   enddo
   return
end subroutine Lower

end module

program main
  use  LinearAlgebra
  implicit none
  integer,parameter :: N=3
  real :: A(N,N)=reshape((/1,2,3,4,5,6,7,8,8/),(/N,N/))
  real :: S(N)=(/12,15,17/)
  real :: ans(N)
  integer :: i
  write(*,*)'Equation:'
  call output(A,S)
  call Gauss_Jordan(A,S,ANS)
  write(*,*)'ANS:'
  do i=1,N
     write(*,"(1x,a1,'=',F8.4)")char(64+i),ANS(i)
  enddo
  stop
end program




	  

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