📄 bcp-1.c
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int global;int func(void);/* These must fail. */int bad0(void) { return __builtin_constant_p(global); }int bad1(void) { return __builtin_constant_p(global++); }inline int bad2(int x) { return __builtin_constant_p(x++); }inline int bad3(int x) { return __builtin_constant_p(x); }inline int bad4(const char *x) { return __builtin_constant_p(x); }int bad5(void) { return bad2(1); }inline int bad6(int x) { return __builtin_constant_p(x+1); }int bad7(void) { return __builtin_constant_p(func()); }int bad8(void) { char buf[10]; return __builtin_constant_p(buf); }int bad9(const char *x) { return __builtin_constant_p(x[123456]); }int bad10(void) { return __builtin_constant_p(&global); }/* These must pass, or we've broken gcc2 functionality. */int good0(void) { return __builtin_constant_p(1); }int good1(void) { return __builtin_constant_p("hi"); }int good2(void) { return __builtin_constant_p((1234 + 45) & ~7); }/* These are extensions to gcc2. Failure indicates an optimization regression. */int opt0(void) { return bad3(1); }int opt1(void) { return bad6(1); }int opt2(void) { return __builtin_constant_p("hi"[0]); }/* * Opt3 is known to fail. It is one of the important cases that glibc * was interested in though, so keep this around as a reminder. * * The solution is to add bits to recover bytes from constant pool * elements given nothing but a constant pool label and an offset. * When we can do that, and we can simplify strlen after the fact, * then we can enable recognition of constant pool labels as constants. *//* int opt3(void) { return bad4("hi"); } *//* Call through tables so -finline-functions can't screw with us. */int (*bad_t0[])(void) = { bad0, bad1, bad5, bad7, bad8, bad10};int (*bad_t1[])(int x) = { bad2, bad3, bad6};int (*bad_t2[])(const char *x) = { bad4, bad9};int (*good_t0[])(void) = { good0, good1, good2};int (*opt_t0[])(void) = { opt0, opt1, opt2 /* , opt3 */};#define N(arr) (sizeof(arr)/sizeof(*arr))int main(){ int i; for (i = 0; i < N(bad_t0); ++i) if ((*bad_t0[i])()) abort(); for (i = 0; i < N(bad_t1); ++i) if ((*bad_t1[i])(1)) abort(); for (i = 0; i < N(bad_t2); ++i) if ((*bad_t2[i])("hi")) abort(); for (i = 0; i < N(good_t0); ++i) if (! (*good_t0[i])()) abort();#ifdef __OPTIMIZE__ for (i = 0; i < N(opt_t0); ++i) if (! (*opt_t0[i])()) abort();#endif exit(0);}
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