📄 1136414_ac_61ms_1016k.cpp
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//应用欧拉函数
//gcd(x,y)=1 则 gcd(x+y,y)=1
//gcd(x,y)>1 则 gcd(x+y,y)>1
#include<stdio.h>
#include<memory.h>
#include<math.h>
int m, k, ftop;
const int len = 1000001;
bool ok[len];
int fact[1000];
int cand[len];
int main()
{
int i, j;
while(scanf("%d %d",&m,&k)!=EOF)
{
memset(ok, false, m + 1);
ftop = 0;
int tm = m;
int euler = m;
const int t = sqrt(tm);
for (i=2; i<=t&&i<=tm; i++)
{
if (tm%i==0)
{
fact[ftop++]=i;
euler = euler/i*(i - 1);
while (tm%i==0) tm/=i;
}
}
if (tm > 1)
{
fact[ftop++] = tm;
euler = euler/tm*(tm - 1);
}
for(i = 0; i < ftop; i ++)
{
if(m%fact[i] == 0)
for(j = fact[i]; j <= m ; j += fact[i])
ok[j] = true;
}
int loop = (k - 1)/euler;
int index = 1 + (k - 1)%euler;
int ct = 0;
for(i = 1; i <= m; i ++)
{
if(!ok[i])
{
ct ++;
if(ct == index)
printf("%d\n",i + loop*m);
}
}
}
return 0;
}
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