⭐ 欢迎来到虫虫下载站! | 📦 资源下载 📁 资源专辑 ℹ️ 关于我们
⭐ 虫虫下载站

📄 anagram.java

📁 java tutorial.sun公司官方出品。java入门书籍。最新版
💻 JAVA
字号:
/* * Copyright (c) 1995 - 2008 Sun Microsystems, Inc.  All rights reserved. * * Redistribution and use in source and binary forms, with or without * modification, are permitted provided that the following conditions * are met: * *   - Redistributions of source code must retain the above copyright *     notice, this list of conditions and the following disclaimer. * *   - Redistributions in binary form must reproduce the above copyright *     notice, this list of conditions and the following disclaimer in the *     documentation and/or other materials provided with the distribution. * *   - Neither the name of Sun Microsystems nor the names of its *     contributors may be used to endorse or promote products derived *     from this software without specific prior written permission. * * THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS * IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, * THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR * PURPOSE ARE DISCLAIMED.  IN NO EVENT SHALL THE COPYRIGHT OWNER OR * CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, * EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, * PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR * PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF * LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING * NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS * SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. */ public class Anagram {    /**     * Tests whether the passed-in strings are anagrams --     * containing the exact same number of each letter.     * Punctuation, case, and order don't matter.     *      * @return true if the strings are anagrams; otherwise, false     */    public static boolean areAnagrams(String string1,                                      String string2) {        String workingCopy1 = removeJunk(string1);        String workingCopy2 = removeJunk(string2);	    workingCopy1 = workingCopy1.toLowerCase();	    workingCopy2 = workingCopy2.toLowerCase();	    workingCopy1 = sort(workingCopy1);	    workingCopy2 = sort(workingCopy2);        return workingCopy1.equals(workingCopy2);    }    /**     * Removes punctuation & spaces -- everything except      * letters from the passed-in string.     *      * @return a stripped copy of the passed-in string     */    protected static String removeJunk(String string) {        int i, len = string.length();        StringBuilder dest = new StringBuilder(len);  		char c;	    for (i = (len - 1); i >= 0; i--) {	        c = string.charAt(i);	        if (Character.isLetter(c)) {		        dest.append(c);	        }	    }        return dest.toString();    }    /**      * Sorts the passed-in string.       *      * @return a sorted copy of the passed-in string     */    protected static String sort(String string) {	    char[] charArray = string.toCharArray();	    java.util.Arrays.sort(charArray);        return new String(charArray);    }    public static void main(String[] args) {        String string1 = "Cosmo and Laine:";        String string2 = "Maid, clean soon!";        System.out.println();        System.out.println("Testing whether the following "                         + "strings are anagrams:");        System.out.println("    String 1: " + string1);        System.out.println("    String 2: " + string2);        System.out.println();        if (areAnagrams(string1, string2)) {            System.out.println("They ARE anagrams!");        } else {            System.out.println("They are NOT anagrams!");        }        System.out.println();    }}

⌨️ 快捷键说明

复制代码 Ctrl + C
搜索代码 Ctrl + F
全屏模式 F11
切换主题 Ctrl + Shift + D
显示快捷键 ?
增大字号 Ctrl + =
减小字号 Ctrl + -