判断回文.bat

来自「高手lxmxn收集的批处理。包括了批处理教程和他写的几十个很经典的代码。」· Batch 代码 · 共 36 行

::Code by lxmxn @ cn-dos.net
::判断输入的字符串是否是回文
::Modified 22:44 2007-1-12

@echo off&setlocal EnableDelayedExpansion
:begin
cls
set /p str=请输入字符串（按空格+回车直接退出）^>
if "%str%"==" " goto :eof
if "%str%"=="" (
	set/p a=        输入错误，请重新输入<nul
	pause>nul
	goto begin
)

set b=0
:redo
if "!str:~%b%,1!"=="" goto yes
set/a c=b+1
if not "!str:~%b%,1!"=="!str:~-%c%,1!" goto no
set/a b+=1
goto redo


:no
echo 字符串【%str%】不是回文……
pause>nul
goto :begin

:yes
echo 字符串【%str%】是回文……
pause>nul
goto :begin