newtonmethod.m

给出插值算子的算法

% function x3=NewtonMethod(x1,x2)
% function varargout=interpolation(x1,x2)
clc
tic
x=0;
t=1;
while (t>1e-2) | abs(f)>=1e-6 | Df~=0
    f=3*x+sin(x)-exp(x);
    Df=3+cos(x)-exp(x);
    y=x-f/Df;
    t=abs(y-x);   
end
x=y;