📄 date.pro
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FUNCTION DATE,YEAR,DAY;+; NAME:; DATE; PURPOSE:; Convert day-of-year to a DD-MMM-YYYY string;; CALLING SEQUENCE:; D_String = DATE(Year, day );; INPUTS:; Year - Integer scalar specifying the year. If the year contains only; two digits, then it is assumed to indicate the number of ; years after 1900. ;; Day - Integer scalar giving number of days after Jan 0 of the ; specified year. Can be larger than 366 ;; OUTPUTS:; D_String - String giving date in format '13-MAR-1986';; RESTRICTIONS:; Will not work for years before 100 AD ; EXAMPLE:; IDL> print, date(1997,279); '6-Oct-1997';; MODIFICATION HISTORY:; D.M. fecit 24 October,1983; Work for years outside of the 19th century W. Landsman September 1997; Converted to IDL V5.0 W. Landsman September 1997;- IF day LE 0 THEN BEGIN D_String = '%DATE-F-DAY.LE.ZERO' ENDIF ELSE BEGIN Last_Day = [31,59,90,120,151,181,212,243,273,304,334,365] LD = [0,INTARR(11)+1] Day_of_Year = Day Months = 'JANFEBMARAPRMAYJUNJULAUGSEPOCTNOVDEC'; Every year that is exactly divisible by 4 is a leap year, except for years; that exactly divisible by 100; these centurial years are leap years only if; they are exactly divisible by 400. IF Year LT 100 THEN Yr = Year + 1900 ELSE Yr = Year Leap = (((Yr MOD 4) EQ 0) AND ((Yr MOD 100) NE 0)) $ OR ((Yr MOD 400) EQ 0) N_Days = 365 + Leap WHILE Day_of_Year GT N_Days DO BEGIN Day_of_Year = Day_of_Year - N_Days Yr = Yr + 1 Leap = (((Yr MOD 4) EQ 0) AND ((Yr MOD 100) NE 0)) $ OR ((Yr MOD 400) EQ 0) N_Days = 365 + Leap END End_Date = '-' + STRTRIM(YR,2) IF Leap THEN Last_Day = Last_Day + LD Last_Month = Day_of_Year LE Last_Day Where_LD = WHERE(Last_Month, N_Month) IF N_Month EQ 12 THEN BEGIN D_String = STRTRIM(Day_of_Year,2) + '-JAN' + End_Date ENDIF ELSE BEGIN LAST_Month = Where_LD[0] Month = STRMID(Months,3*Last_Month,3) Day_of_Month = Day_of_Year - Last_Day[Last_Month-1] D_String = STRTRIM(Day_of_Month,2) + '-' + Month + End_Date END END RETURN,D_String END
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