📄 ymd2dn.pro
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;-------------------------------------------------------------;+; NAME:; YMD2DN; PURPOSE:; Convert from year, month, day to day number of year.; CATEGORY:; CALLING SEQUENCE:; dy = ymd2dn(yr,m,d); INPUTS:; yr = year (like 1988). scalar or vector; m = month number (like 11 = Nov). scalar or vector; d = day of month (like 5). scalar or vector; KEYWORD PARAMETERS:; OUTPUTS:; dy = day number in year (like 310). out; COMMON BLOCKS:; NOTES:; MODIFICATION HISTORY:; Written by R. Sterner, 20 June, 1985.; Johns Hopkins University Applied Physics Laboratory.; RES 18 Sep, 1989 --- converted to SUN; R. Sterner, 1997 Feb 3 --- Made work for arrays.;; Copyright (C) 1985, Johns Hopkins University/Applied Physics Laboratory; This software may be used, copied, or redistributed as long as it is not; sold and this copyright notice is reproduced on each copy made. This; routine is provided as is without any express or implied warranties; whatsoever. Other limitations apply as described in the file disclaimer.txt.; Converted to IDL V5.0 W. Landsman 2-Jan-1998;-;------------------------------------------------------------- function ymd2dn,yr,m,d, help=hlp if (n_params(0) lt 3) or keyword_set(hlp) then begin print,' Convert from year, month, day to day number of year.' print,' dy = ymd2dn(yr,m,d)' print,' yr = year (like 1988). in' print,' m = month number (like 11 = Nov). in' print,' d = day of month (like 5). in' print,' dy = day number in year (like 310). out' return, -1 endif ;---- Days before start of each month (non-leap year) ----- idays = [0,31,59,90,120,151,181,212,243,273,304,334,366] ;---- Correct for leap year if month ge 3 ------------- lpyr = (((yr mod 4) eq 0) and ((yr mod 100) ne 0)) $ or ((yr mod 400) eq 0) and (m ge 3) dy = d + idays[m-1] + lpyr return, dy end
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