📄 nik.m
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function [tnk,dnk]=nik(k,nn,t1);
% [tnk,dnk]=nik(k,nn,t1)
% B样条曲线的基函数
% n=nn+2为控制点数目
% k-1为曲线次数
n=nn+2;
eps=1.0e-3;
t(1:k)=0.0;
if n>k
for i=k+1:n;
t(i)=(i-k)/(n-(k-1));
end
end
t(n+1:n+k)=1.0;
for i=1:n+k
tn(i,1)=0.0;
end
for i=k:n
if and((t(i+1)-t1)>eps,(t1-t(i))>eps)
tn(i,1)=1.0;
elseif(abs(t1-t(i))<eps)
tn(i,1)=1.0;
else
tn(i,1)=0.0;
end
end
if abs(t1)<eps
tn(k,1)=1.0;
elseif abs(t1-1.0)<eps
tn(n,1)=1.0;
end
for kk=2:k
for i=1:n+k-kk
if (t(i+kk-1)-t(i))<eps
delt1=0.0;
else
delt1=(t1-t(i))/(t(i+kk-1)-t(i));
end
if (t(i+kk)-t(i+1))<eps
delt2=0.0;
else
delt2=(t(i+kk)-t1)/(t(i+kk)-t(i+1));
end
tn(i,kk)=tn(i,kk-1)*delt1+tn(i+1,kk-1)*delt2;
if kk==k
if(t(i+k-1)-t(i))<eps
part1=0.0;
else
part1=tn(i,kk-1)/(t(i+k-1)-t(i));
end
if(t(i+k)-t(i+1))<eps
part2=0.0;
else
part2=tn(i+1,kk-1)/(t(i+k)-t(i+1));
end
dn(i,kk)=(k-1)*(part1-part2);
end
end
end
tnk=tn(1:n,k);
dnk=dn(1:n,k);
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