ip_01_05.m

来自「quickly search for the fourier series」· M 代码 · 共 20 行

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% MATLAB script for Illustrative Problem 5.1. 
df=0.01;
fs=10;
ts=1/fs;
t=[-5:ts:5];
x1=zeros(size(t));
x1(41:51)=t(41:51)+1;
x1(52:61)=ones(size(x1(52:61)));
x2=zeros(size(t));
x2(51:71)=x1(41:61);
[X1,x11,df1]=fftseq(x1,ts,df);  % X1 is exactly the discrete time fourier 
[X2,x21,df2]=fftseq(x2,ts,df);
X11=X1/fs; % X1 is tranversed from the discrete-time to continuous-time
X21=X2/fs;
f=[0:df1:df1*(length(x11)-1)]-fs/2;

plot(f,fftshift(abs(X11)))

figure
plot(f(500:525),fftshift(angle(X11(500:525))),f(500:525),fftshift(angle(X21(500:525))),'--')

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