netorder.c

来自「linux环境下的网络字节序的问题」· C语言 代码 · 共 28 行

C
28
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/* netorder.c */#include <stdio.h>#include <netinet/in.h>int main(void){    int i;    union {	int s;	char c[4];    } un;    un.s = htonl(0x01020304);    for (i = 0; i < 4; i++)	printf("c[%d] = %d\t", i, un.c[i]);    printf("\n&s = %p, &c[0] = %p\n", &un.s, &un.c[0]);    if (un.c[0] == 1)	printf("big-endian\n");    else if (un.c[0] == 4)	printf("little-endian\n");    else	printf("unknown\n");    return 0;}

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