netorder.c
来自「linux环境下的网络字节序的问题」· C语言 代码 · 共 28 行
C
28 行
/* netorder.c */#include <stdio.h>#include <netinet/in.h>int main(void){ int i; union { int s; char c[4]; } un; un.s = htonl(0x01020304); for (i = 0; i < 4; i++) printf("c[%d] = %d\t", i, un.c[i]); printf("\n&s = %p, &c[0] = %p\n", &un.s, &un.c[0]); if (un.c[0] == 1) printf("big-endian\n"); else if (un.c[0] == 4) printf("little-endian\n"); else printf("unknown\n"); return 0;}
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