📄 pid-identifier.sh
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#!/bin/bash# pid-identifier.sh:# Gives complete path name to process associated with pid.ARGNO=1 # Number of arguments the script expects.E_WRONGARGS=65E_BADPID=66E_NOSUCHPROCESS=67E_NOPERMISSION=68PROCFILE=exeif [ $# -ne $ARGNO ]then echo "Usage: `basename $0` PID-number" >&2 # Error message >stderr. exit $E_WRONGARGSfi pidno=$( ps ax | grep $1 | awk '{ print $1 }' | grep $1 )# Checks for pid in "ps" listing, field #1.# Then makes sure it is the actual process, not the process invoked by this script.# The last "grep $1" filters out this possibility.## pidno=$( ps ax | awk '{ print $1 }' | grep $1 )# also works, as Teemu Huovila, points out.if [ -z "$pidno" ] # If, after all the filtering, the result is a zero-length string,then #+ no running process corresponds to the pid given. echo "No such process running." exit $E_NOSUCHPROCESSfi # Alternatively:# if ! ps $1 > /dev/null 2>&1# then # no running process corresponds to the pid given.# echo "No such process running."# exit $E_NOSUCHPROCESS# fi# To simplify the entire process, use "pidof".if [ ! -r "/proc/$1/$PROCFILE" ] # Check for read permission.then echo "Process $1 running, but..." echo "Can't get read permission on /proc/$1/$PROCFILE." exit $E_NOPERMISSION # Ordinary user can't access some files in /proc.fi # The last two tests may be replaced by:# if ! kill -0 $1 > /dev/null 2>&1 # '0' is not a signal, but # this will test whether it is possible # to send a signal to the process.# then echo "PID doesn't exist or you're not its owner" >&2# exit $E_BADPID# fiexe_file=$( ls -l /proc/$1 | grep "exe" | awk '{ print $11 }' )# Or exe_file=$( ls -l /proc/$1/exe | awk '{print $11}' )## /proc/pid-number/exe is a symbolic link#+ to the complete path name of the invoking process.if [ -e "$exe_file" ] # If /proc/pid-number/exe exists,then #+ then the corresponding process exists. echo "Process #$1 invoked by $exe_file."else echo "No such process running."fi # This elaborate script can *almost* be replaced by# ps ax | grep $1 | awk '{ print $5 }'# However, this will not work...#+ because the fifth field of 'ps' is argv[0] of the process,#+ not the executable file path.## However, either of the following would work.# find /proc/$1/exe -printf '%l\n'# lsof -aFn -p $1 -d txt | sed -ne 's/^n//p'# Additional commentary by Stephane Chazelas.exit 0
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