ex28.sh

来自「Shall高级编程」· Shell 代码 · 共 50 行

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#!/bin/bashLIMIT=19  # Upper limitechoecho "Printing Numbers 1 through 20 (but not 3 and 11)."a=0while [ $a -le "$LIMIT" ]do a=$(($a+1)) if [ "$a" -eq 3 ] || [ "$a" -eq 11 ]  # Excludes 3 and 11. then   continue      # Skip rest of this particular loop iteration. fi echo -n "$a "   # This will not execute for 3 and 11.done # Exercise:# Why does loop print up to 20?echo; echoecho Printing Numbers 1 through 20, but something happens after 2.################################################################### Same loop, but substituting 'break' for 'continue'.a=0while [ "$a" -le "$LIMIT" ]do a=$(($a+1)) if [ "$a" -gt 2 ] then   break  # Skip entire rest of loop. fi echo -n "$a "doneecho; echo; echoexit 0

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