📄 ex28.sh
字号:
#!/bin/bashLIMIT=19 # Upper limitechoecho "Printing Numbers 1 through 20 (but not 3 and 11)."a=0while [ $a -le "$LIMIT" ]do a=$(($a+1)) if [ "$a" -eq 3 ] || [ "$a" -eq 11 ] # Excludes 3 and 11. then continue # Skip rest of this particular loop iteration. fi echo -n "$a " # This will not execute for 3 and 11.done # Exercise:# Why does loop print up to 20?echo; echoecho Printing Numbers 1 through 20, but something happens after 2.################################################################### Same loop, but substituting 'break' for 'continue'.a=0while [ "$a" -le "$LIMIT" ]do a=$(($a+1)) if [ "$a" -gt 2 ] then break # Skip entire rest of loop. fi echo -n "$a "doneecho; echo; echoexit 0
⌨️ 快捷键说明
复制代码
Ctrl + C
搜索代码
Ctrl + F
全屏模式
F11
切换主题
Ctrl + Shift + D
显示快捷键
?
增大字号
Ctrl + =
减小字号
Ctrl + -