📄 tryit_view.asp@filename=tryajax_httprequest_js

📁 W3Schools tutorial..web designing

💻 ASP@FILENAME=TRYAJAX_HTTPREQUEST_JS

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<html>
<head>
<script type="text/javascript">
var xmlhttp;
function loadXMLDoc(url)
{
xmlhttp=null;
if (window.XMLHttpRequest)
  {// code for IE7, Firefox, Opera, etc.
  xmlhttp=new XMLHttpRequest();
  }
else if (window.ActiveXObject)
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
if (xmlhttp!=null)
  {
  xmlhttp.onreadystatechange=state_Change;
  xmlhttp.open("GET",url,true);
  xmlhttp.send(null);
  }
else
  {
  alert("Your browser does not support XMLHTTP.");
  }
}

function state_Change()
{
if (xmlhttp.readyState==4)
  {// 4 = "loaded"
  if (xmlhttp.status==200)
    {// 200 = "OK"
    document.getElementById('A1').innerHTML=xmlhttp.status;
    document.getElementById('A2').innerHTML=xmlhttp.statusText;
    document.getElementById('A3').innerHTML=xmlhttp.responseText;
    }
  else
    {
    alert("Problem retrieving XML data:" + xmlhttp.statusText);
    }
  }
}
</script>
</head>

<body>
<h2>Using the HttpRequest Object</h2>

<p><b>Status:</b>
<span id="A1"></span>
</p>

<p><b>Status text:</b>
<span id="A2"></span>
</p>

<p><b>Response:</b>
<br /><span id="A3"></span>
</p>

<button onclick="loadXMLDoc('note.xml')">Get XML</button>

</body>
</html>

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