hilbertbucketorder.java

Sunflow是一个照片级的渲染系统

package org.sunflow.core.bucket;

import org.sunflow.core.BucketOrder;

public class HilbertBucketOrder implements BucketOrder {
    public int[] getBucketSequence(int nbw, int nbh) {
        int hi = 0; // hilbert curve index
        int hn = 0; // hilbert curve order
        while (((1 << hn) < nbw || (1 << hn) < nbh) && hn < 16)
            hn++; // fit to number of buckets
        int hN = 1 << (2 * hn); // number of hilbert buckets - 2**2n
        int n = nbw * nbh; // total number of buckets
        int[] coords = new int[2 * n]; // storage for bucket coordinates
        for (int i = 0; i < n; i++) {
            int hx, hy;
            do {
                // s is the hilbert index, shifted to start in the middle
                int s = hi; // (hi + (hN >> 1)) & (hN - 1);
                // int n = hn;
                // adapted from Hacker's Delight
                int comp, swap, cs, t, sr;
                s = s | (0x55555555 << (2 * hn)); // Pad s on left with 01
                sr = (s >>> 1) & 0x55555555; // (no change) groups.
                cs = ((s & 0x55555555) + sr) ^ 0x55555555;// Compute
                // complement
                // & swap info in
                // two-bit groups.
                // Parallel prefix xor op to propagate both complement
                // and swap info together from left to right (there is
                // no step "cs ^= cs >> 1", so in effect it computes
                // two independent parallel prefix operations on two
                // interleaved sets of sixteen bits).
                cs = cs ^ (cs >>> 2);
                cs = cs ^ (cs >>> 4);
                cs = cs ^ (cs >>> 8);
                cs = cs ^ (cs >>> 16);
                swap = cs & 0x55555555; // Separate the swap and
                comp = (cs >>> 1) & 0x55555555; // complement bits.
                t = (s & swap) ^ comp; // Calculate x and y in
                s = s ^ sr ^ t ^ (t << 1); // the odd & even bit
                // positions, resp.
                s = s & ((1 << 2 * hn) - 1); // Clear out any junk
                // on the left (unpad).
                // Now "unshuffle" to separate the x and y bits.
                t = (s ^ (s >>> 1)) & 0x22222222;
                s = s ^ t ^ (t << 1);
                t = (s ^ (s >>> 2)) & 0x0C0C0C0C;
                s = s ^ t ^ (t << 2);
                t = (s ^ (s >>> 4)) & 0x00F000F0;
                s = s ^ t ^ (t << 4);
                t = (s ^ (s >>> 8)) & 0x0000FF00;
                s = s ^ t ^ (t << 8);
                hx = s >>> 16; // Assign the two halves
                hy = s & 0xFFFF; // of t to x and y.
                hi++;
            } while ((hx >= nbw || hy >= nbh || hx < 0 || hy < 0) && hi < hN);
            coords[2 * i + 0] = hx;
            coords[2 * i + 1] = hy;
        }
        return coords;
    }
}