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📄 2003-march.txt

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partners and 3D-software industry advocates to interact with Spatial'sexecutives and developers. Government and university researchers areencouraged to attend as well, since presentations and discussions willtraverse a wide variety of subjects and applications of Spatial'stechnology. Topics will include, but not be limited to, ACIS, InterOp, andCAA V5. Elaine Hinman-Sweeney and Arlo Ames of Sandia National Laboratorieswill present a joint keynote speech.In addition to presentations, attendees will have access to the Insiders'Workshop, in which Spatial technical staff will be available to answerone-on-one questions and conduct demonstrations. Plus, there will be plentyof opportunities to interact and network with other attendees and Spatialstaff!Registration is available now. Register early and save-?before April 30registration is only $395! Company and group registrations are discounted,and if more than one person registers from your company, the additionalregistrants are only $150 each!For further information about the event, or to register for this event, goto our Web site at:http://www.spatial.com/summit03We hope to see you in June!From tangency"<tangency@indiatimes.com  Wed Mar 12 22:50:42 2003From: tangency"<tangency@indiatimes.com (tangency)Date: Thu, 13 Mar 2003 04:20:42 +0530Subject: [Acis-alliance] projected areaMessage-ID: <200303122235.EAA24421@WS0005.indiatimes.com>--=_MAILER_ATTACH_BOUNDARY1_20033134420421681692777Content-Type: text/plain; charset=us-asciiHello everybody,I am a new member to the group, and I hope that I can learn a lot and help a lot.I am facing a certain problem and was wondering if anyone could give me a few pointers.I am involved in finding the projected area of a solid in a certain direction.  I have been looking at many ways in which to do it, but all of them failed.My only way which is looking reasonable is to use api_project_wire, but one of the problems I face is how to do create a surface from the bunch of wires projected and how to I get the area off this.Anyhelp in this approach or any alternative approach will be deeply appreciated.thank you so much people :) Get Your Private, Free E-mail from Indiatimes at  http://email.indiatimes.comBuy the best in Movies at http://www.videos.indiatimes.comBid for Air Tickets @ Re.1 on Air Sahara Flights. Just log on to http://airsahara.indiatimes.com and Bid Now !--=_MAILER_ATTACH_BOUNDARY1_20033134420421681692777Content-Type: text/html; charset=us-ascii<P>Hello everybody,</P><P>I am a new member to the group, and I hope that I can learn a lot and help a lot.</P><P>I am facing a certain problem and was wondering if anyone could give me a few pointers.</P><P>I am involved in finding the projected area of a solid in a certain direction.&nbsp; I have been looking at many ways in which to do it, but all of them failed.</P><P>My only way which is looking reasonable is to use api_project_wire, but one of the problems I face is how to do create a surface from the bunch of wires projected and how to I get the area off this.</P><P>Anyhelp in this approach or any alternative approach will be deeply appreciated.</P><P>thank you so much people </P><P>:)</P><P>&nbsp;</P><hr><font face="Arial" size="2"><b>Get Your Private, Free E-mail from Indiatimes at  </font><a href="http://email.indiatimes.com"><font face="Arial" size="2">http://email.indiatimes.com</a></b><br>Buy the best in Movies at <A href="http://www.videos.indiatimes.com">http://www.videos.indiatimes.com</A><br>Bid for <b>Air Tickets @ Re.1</b> on Air Sahara Flights. Just log on to <a href="http://airsahara.indiatimes.com">http://airsahara.indiatimes.com</a> and Bid Now !</font>--=_MAILER_ATTACH_BOUNDARY1_20033134420421681692777--From alames@sandia.gov  Thu Mar 13 22:12:50 2003From: alames@sandia.gov (Ames, Arlo)Date: Thu, 13 Mar 2003 15:12:50 -0700Subject: [Acis-alliance] projected areaMessage-ID: <03781128C7B74B4DBC27C55859C9D738FDB5D7@es06snlnt.sandia.gov>This message is in MIME format. Since your mail reader does not understandthis format, some or all of this message may not be legible.------_=_NextPart_001_01C2E9AC.79F5E500Content-Type: text/plain; charset=iso-8859-1Content-Transfer-Encoding: 7bitYou're on a reasonable track.  Imprint all the wires against each other,then walk the resultant graph.  You'll want to make sure you includesilhouette edges in the set of wires you project.  It is almost easier ifyou do the projection yourself, as it's helpful to know whether theprojection of each edges is locally inside or outside of the model.  Wherethe projection is locally not inside of the model, you have a candidateboundary edge, while if the projection (forward or backward along theprojection direction) is locally inside, you don't really care aboutprojecting the edge.  Note that you're interested in regions of each edge,as the curved nature of everything can leave you with an edge that changesclassification many times along its length.  If you have all the projectionsof all the coedges that don't locally project to inside the solid, you havea set of coedges that might be boundaries.  Find the exterior-mostconcatenatable loop and you have the exterior of the shadow.  The interiorrequires the same sort of logic, but is worse because even if a loop islocally visible, it might be globally in shadow; you will likely requiresome ray firing to disambiguate. Alternatively, if an approximation will do, facet the model, render all thefacets in white on a black pixmap in GL, then count the nonblack pixels.The approximation will be limited in accuracy to the accuracy of yourfacetization and the resolution of your pixmap, but it will go fast;possibly a lot faster than the first approach, depending on the complexityof the model. Arlo-----Original Message-----From: tangency [mailto:tangency@indiatimes.com]Sent: Wednesday, March 12, 2003 3:51 PMTo: acis-alliance@cs.columbia.eduSubject: [Acis-alliance] projected areaHello everybody,I am a new member to the group, and I hope that I can learn a lot and help alot.I am facing a certain problem and was wondering if anyone could give me afew pointers.I am involved in finding the projected area of a solid in a certaindirection.  I have been looking at many ways in which to do it, but all ofthem failed.My only way which is looking reasonable is to use api_project_wire, but oneof the problems I face is how to do create a surface from the bunch of wiresprojected and how to I get the area off this.Anyhelp in this approach or any alternative approach will be deeplyappreciated.thank you so much people :)   _____  Get Your Private, Free E-mail from Indiatimes at<http://email.indiatimes.com> http://email.indiatimes.comBuy the best in Movies at http://www.videos.indiatimes.com<http://www.videos.indiatimes.com> Bid for Air Tickets @ Re.1 on Air Sahara Flights. Just log on tohttp://airsahara.indiatimes.com <http://airsahara.indiatimes.com>  and BidNow ! ------_=_NextPart_001_01C2E9AC.79F5E500Content-Type: text/html; charset=iso-8859-1Content-Transfer-Encoding: 7bit<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"><HTML><HEAD><META HTTP-EQUIV="Content-Type" CONTENT="text/html; charset=ISO-8859-1"><META content="MSHTML 6.00.2600.0" name=GENERATOR></HEAD><BODY><DIV><SPAN class=664030422-13032003><FONT face=Arial color=#0000ff size=2>You're on a reasonable track.&nbsp; Imprint all the wires against each other, then walk the resultant graph.&nbsp; You'll want to make sure you include silhouette edges in the set of wires you project.&nbsp; It is almost easier if you do the projection yourself, as it's helpful to know whether the projection of each edges is locally inside or outside of the model.&nbsp; Where the projection is locally not inside of the model, you have a candidate boundary edge, while if the projection (forward or backward along the projection direction) is locally inside, you don't really care about projecting the edge.&nbsp; Note that you're interested in regions of each edge, as the curved nature of everything can leave you with an edge that changes classification many times along its length.&nbsp; If you have all the projections of all the coedges that don't locally project to inside the solid, you have a set of coedges that might be boundaries.&nbsp; Find the exterior-most concatenatable loop and you have the exterior of the shadow.&nbsp; The interior requires the same sort of logic, but is worse because even if a loop is locally visible, it might be globally in shadow; you will likely require some ray firing to disambiguate.</FONT></SPAN></DIV><DIV><SPAN class=664030422-13032003><FONT face=Arial color=#0000ff size=2></FONT></SPAN>&nbsp;</DIV><DIV><SPAN class=664030422-13032003><FONT face=Arial color=#0000ff size=2>Alternatively, if an approximation will do, facet the model, render all the facets in white on a black pixmap in GL, then count the nonblack pixels.&nbsp; The approximation will be limited in accuracy to the accuracy of your facetization and the resolution of your pixmap, but it will go fast; possibly a lot faster than the first approach, depending on the complexity of the model.</FONT></SPAN></DIV><DIV><SPAN class=664030422-13032003><FONT face=Arial color=#0000ff size=2></FONT></SPAN>&nbsp;</DIV><DIV><SPAN class=664030422-13032003><FONT face=Arial color=#0000ff size=2>Arlo</FONT></SPAN></DIV><BLOCKQUOTE>  <DIV class=OutlookMessageHeader dir=ltr align=left><FONT face=Tahoma   size=2>-----Original Message-----<BR><B>From:</B> tangency   [mailto:tangency@indiatimes.com]<BR><B>Sent:</B> Wednesday, March 12, 2003   3:51 PM<BR><B>To:</B> acis-alliance@cs.columbia.edu<BR><B>Subject:</B>   [Acis-alliance] projected area<BR><BR></FONT></DIV>  <P>Hello everybody,</P>  <P>I am a new member to the group, and I hope that I can learn a lot and help   a lot.</P>  <P>I am facing a certain problem and was wondering if anyone could give me a   few pointers.</P>  <P>I am involved in finding the projected area of a solid in a certain   direction.&nbsp; I have been looking at many ways in which to do it, but all   of them failed.</P>  <P>My only way which is looking reasonable is to use api_project_wire, but one   of the problems I face is how to do create a surface from the bunch of wires   projected and how to I get the area off this.</P>  <P>Anyhelp in this approach or any alternative approach will be deeply   appreciated.</P>  <P>thank you so much people </P>  <P>:)</P>  <P>&nbsp;</P>  <HR>  <FONT face=Arial size=2><B>Get Your Private, Free E-mail from Indiatimes at   </FONT><A href="http://email.indiatimes.com"><FONT face=Arial   size=2>http://email.indiatimes.com</A></B><BR>Buy the best in Movies at <A   href="http://www.videos.indiatimes.com">http://www.videos.indiatimes.com</A><BR>Bid   for <B>Air Tickets @ Re.1</B> on Air Sahara Flights. Just log on to <A   href="http://airsahara.indiatimes.com">http://airsahara.indiatimes.com</A> and   Bid Now !</FONT> </BLOCKQUOTE></BODY></HTML>------_=_NextPart_001_01C2E9AC.79F5E500--From kaufmann@ims.tuwien.ac.at  Fri Mar 14 17:05:04 2003From: kaufmann@ims.tuwien.ac.at (Hannes Kaufmann)Date: Fri, 14 Mar 2003 18:05:04 +0100Subject: [Acis-alliance] intersection curveMessage-ID: <3E720BC0.E329A1D0@ims.tuwien.ac.at>

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