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📄 xajaxresponsetest.php

📁 PHP+Ajax网站开发典型实例
💻 PHP
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<?phprequire_once("../xajax.inc.php");function showOutput(){	$testResponse = new xajaxResponse();	$testResponse->addAlert("Hello");//	$testResponseOutput = htmlspecialchars($testResponse->getXML());		$testResponse2 = new xajaxResponse();	$testResponse2->loadXML($testResponse->getXML());	$testResponse2->addReplace("this", "is", "a", "replacement");	$testResponseOutput = htmlspecialchars($testResponse2->getXML());			$objResponse = new xajaxResponse();	$objResponse->addAssign("submittedDiv", "innerHTML", $testResponseOutput);	return $objResponse;}$xajax = new xajax();//$xajax->debugOn();$xajax->registerFunction("showOutput");$xajax->processRequests();$xajax->autoCompressJavascript("../xajax_js/xajax.js");?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"        "http://www.w3.org/TR/2000/REC-xhtml1-20000126/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><title>xajaxResponse Test | xajax Tests</title><?php $xajax->printJavascript("../") ?></head><body><h2><a href="index.php">xajax Tests</a></h2><h1>xajaxResponse Test</h1><form id="testForm1" onsubmit="return false;"><p><input type="submit" value="Show Response XML" onclick="xajax_showOutput(); return false;" /></p></form><div id="submittedDiv"></div></body></html>

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