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// a example to test the level of optimisation// --------------------------------------------int nn=2000;real cpu=0; mesh Th=square(nn,nn);verbosity=10; fespace Vh(Th,P1); // P1 FE space Vh uh,vh; // unkown and test function. func f=1; // right hand side function func g=0; // boundary condition function problem laplace2(uh,vh,solver=UMFPACK,tgv=1e30) = // definion of the problem int2d(Th)( dx(uh)*dx(vh) + dy(uh)*dy(vh) ) // bilinear form + int1d(Th,1)( uh*vh) + int1d(Th,1)( - vh) + int2d(Th)( -f*vh ) // linear form + on(2,3,4,uh=g) ; // boundary condition form cpu=clock(); laplace2; // solve the problem plot(uh); // to see the result cout << "-- lap UMFPACK " << nn << "x" << nn << " : " << -cpu+clock() << " s, max =" << uh[].max << endl;// plot(uh,ps="lap1-cpu.eps",value=true);
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