bb.edp

FreeFem++可以生成高质量的有限元网格。可以用于流体力学

//  Computation of the eigen value and eigen vector of the 
// Dirichlet problem  on square $]0,\pi[^2$
// ----------------------------------------
// we use the inverse shift mode 
// the shift is given with sigma real
// -------------------------------------
//  find $\lamda$ such that:
// $$  \int_{\omega}  \nabla u_ \nabla v = \lamba \int_{\omega} u \nabla v  $$
verbosity=1;
mesh Th=square(20,20,[pi*x,pi*y]);
fespace Vh(Th,P2);
Vh u1,u2;


real sigma = 00;  // value of the shift 

varf  a(u1,u2)= int2d(Th)(  dx(u1)*dx(u2) + dy(u1)*dy(u2) - sigma* u1*u2 )
                    +  on(1,2,3,4,u1=0) ;  // Boundary condition
                   
varf b([u1],[u2]) = int2d(Th)(  u1*u2 ) ; // no  Boundary condition

matrix A= a(Vh,Vh,solver=CG,factorize=0); 
matrix B= b(Vh,Vh,solver=CG,eps=1e-20); 

// important remark:
// the boundary condition is make with exact penalisation:
//     we put 1e30=tgv  on the diagonal term of the lock degre of freedom.
//  So take dirichlet boundary condition just on $a$ variationnal form
// and not on  $b$ variationnanl form.
// because we solve
//  $$ w=A^-1*B*v $$

int nev=20;  // number of computed eigen valeu close to sigma

real[int] ev(nev); // to store nev eigein value
Vh[int] eV(nev);   // to store nev eigen vector


int k=EigenValue(A,B,sym=true,sigma=sigma,value=ev,vector=eV,tol=1e-10,maxit=0,ncv=0);
//   tol= the tolerace
//   maxit= the maximal iteration see arpack doc.
//   ncv   see arpack doc.
//  the return value is number of converged eigen value.

for (int i=0;i<k;i++)
{
  u1=eV[i];
  real gg = int2d(Th)(dx(u1)*dx(u1) + dy(u1)*dy(u1));
  real mm= int2d(Th)(u1*u1) ;
  cout << " ---- " <<  i<< " " << ev[i]<< " err= " 
       <<int2d(Th)(dx(u1)*dx(u1) + dy(u1)*dy(u1) - (ev[i])*u1*u1) << " --- "<<endl;
  plot(eV[i],cmm="Eigen  Vector "+i+" valeur =" + ev[i]  ,wait=1,value=1,ps="eigen"+i+".eps");
}