📄 lapeigenvalue.edp
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// Computation of the eigen value and eigen vector of the // Dirichlet problem on square $]0,\pi[^2$// ----------------------------------------// we use the inverse shift mode // the shift is given with sigma real// -------------------------------------// find $\lamda$ such that:// $$ \int_{\omega} \nabla u_ \nabla v = \lamba \int_{\omega} u \nabla v $$verbosity=1;mesh Th=square(20,20,[pi*x,pi*y]);fespace Vh(Th,P2);Vh u1,u2;real sigma = 00; // value of the shift varf a(u1,u2)= int2d(Th)( dx(u1)*dx(u2) + dy(u1)*dy(u2) - sigma* u1*u2 ) + on(1,2,3,4,u1=0) ; // Boundary condition varf b([u1],[u2]) = int2d(Th)( u1*u2 ) ; // no Boundary conditionmatrix A= a(Vh,Vh,solver=Crout,factorize=1); matrix B= b(Vh,Vh,solver=CG,eps=1e-20); // important remark:// the boundary condition is make with exact penalisation:// we put 1e30=tgv on the diagonal term of the lock degre of freedom.// So take dirichlet boundary condition just on $a$ variationnal form// and not on $b$ variationnanl form.// because we solve// $$ w=A^-1*B*v $$int nev=20; // number of computed eigen valeu close to sigmareal[int] ev(nev); // to store nev eigein valueVh[int] eV(nev); // to store nev eigen vectorint k=EigenValue(A,B,sym=true,sigma=sigma,value=ev,vector=eV,tol=1e-10,maxit=0,ncv=0);// tol= the tolerace// maxit= the maximal iteration see arpack doc.// ncv see arpack doc.// the return value is number of converged eigen value.int nerr=0;real[int] eev(36);eev=1e100;for(int i=1,k=0;i<6;++i)for(int j=1;j<6;++j) eev[k++]=i*i+j*j;eev.sort;cout << eev << endl;for (int i=0;i<k;i++){ u1=eV[i]; real gg = int2d(Th)(dx(u1)*dx(u1) + dy(u1)*dy(u1)); real mm= int2d(Th)(u1*u1) ; real err = int2d(Th)(dx(u1)*dx(u1) + dy(u1)*dy(u1) - (ev[i])*u1*u1) ; if(abs(err) > 1e-6) nerr++; if(abs(ev[i]-eev[i]) > 1e-1) nerr++; cout << " ---- " << i<< " " << ev[i] << " == " << eev[i] << " err= " << err << " --- "<<endl; plot(eV[i],cmm="Eigen Vector "+i+" valeur =" + ev[i] ,wait=1,value=1,ps="eigen"+i+".eps");}assert(nerr==0);
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