储蓄顾问.frm

来自「算法教案」· FRM 代码 · 共 77 行

VERSION 5.00
Begin VB.Form Form1 
   Caption         =   "储蓄顾问"
   ClientHeight    =   2730
   ClientLeft      =   60
   ClientTop       =   450
   ClientWidth     =   4680
   LinkTopic       =   "Form1"
   ScaleHeight     =   2730
   ScaleWidth      =   4680
   StartUpPosition =   3  '窗口缺省
   Begin VB.CommandButton Command1 
      Caption         =   "需要存多少年？"
      Height          =   495
      Left            =   120
      TabIndex        =   5
      Top             =   1800
      Width           =   1695
   End
   Begin VB.TextBox Text3 
      Height          =   375
      Left            =   2280
      Locked          =   -1  'True
      TabIndex        =   4
      Top             =   1920
      Width           =   1815
   End
   Begin VB.TextBox Text2 
      Height          =   375
      Left            =   2280
      TabIndex        =   3
      Top             =   1080
      Width           =   1815
   End
   Begin VB.TextBox Text1 
      Height          =   375
      Left            =   2280
      TabIndex        =   2
      Top             =   360
      Width           =   1815
   End
   Begin VB.Label Label2 
      Caption         =   "请输入税后本息："
      Height          =   375
      Left            =   240
      TabIndex        =   1
      Top             =   1080
      Width           =   1575
   End
   Begin VB.Label Label1 
      Caption         =   "请输入存款额："
      Height          =   375
      Left            =   240
      TabIndex        =   0
      Top             =   360
      Width           =   1455
   End
End
Attribute VB_Name = "Form1"
Attribute VB_GlobalNameSpace = False
Attribute VB_Creatable = False
Attribute VB_PredeclaredId = True
Attribute VB_Exposed = False
Private Sub Command1_Click()
    Dim x As Double
    m = Val(Text1.Text)
    k = Val(Text2.Text)
    x = (k - m) / (0.028 * m)
    y = Fix(x)
    If y < x Then y = y + 1
    Text3.Text = "存款应为" + Str(y) + "年"
End Sub

Private Sub Text1_Click()
    Text1.Text = "": Text2.Text = "": Text3.Text = ""
End Sub