4349618_ce.cpp

北大大牛代码 1240道题的原代码 超级权威

#include <stdio.h>

char zad[250000];

char *
incl (char *op, __int64 *in, int64 *cl)
{
  int64 in1, cl1, in2, cl2;

  switch (*op)
    {
    case 'V':
      *in = 1;
      *cl = 1;
      return op + 2;

    case 'C':
      return incl (op + 2, cl, in);

    case 'U':
      op = incl (op + 2, &in1, &cl1);
      op = incl (op, &in2, &cl2);
      *in = in1 + in2;
      *cl = (cl1 > cl2 ? cl1 : cl2);
      return op;
    }
}

int main()
{
  int64 in, cl;

  while (1)
    {
      if (!gets (zad))
	return 0;

      if (!*zad)
	return 0;

      incl (zad, &in, &cl);
      printf ("%I64d\n", in);
    }
    return 0;
}