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📄 2311028_re.cpp

📁 北大大牛代码 1240道题的原代码 超级权威
💻 CPP
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# include <stdio.h>
# include <math.h>
# include <algorithm>
# define MAX 200011
using namespace std;

typedef long stack;
struct node
{
	double x, y;
}Q[MAX];

long n, L, low;
long lowx, lowy;
stack p, s[MAX];

bool cmp(struct node a,struct node b)
{
	if(a.x==lowx&&a.y==lowy)
		return 1;
	if(b.x==lowx&&b.y==lowy)
		return 0;
	if((a.x-lowx)*(b.y-lowy)==(b.x-lowx)*(a.y-lowy))
		return (a.x-lowx)*(a.x-lowx)+(a.y-lowy)*(a.y-lowy)<(b.x-lowx)*(b.x-lowx)+(b.y-lowy)*(b.y-lowy);
	return (a.x-lowx)*(b.y-lowy)-(b.x-lowx)*(a.y-lowy) > 0;
}

void GRAHAM_SCAN()
{
	int i;

	s[0] = 0;
	i = 1;
	//while(i<n-1&&(Q[i].x-lowx)*(Q[i+1].y-lowy)==(Q[i+1].x-lowx)*(Q[i].y-lowy))
		//i++;
	s[1] = i++;s[2] = i++;
	p = 2;
	while(i < n)
	{
		//output();		
		if(i<n-1&&(Q[i].x-lowx)*(Q[i+1].y-lowy)==(Q[i+1].x-lowx)*(Q[i].y-lowy))
		{
			i++;
			//printf("WDFSDFsd");
			continue;
		}
		while((Q[s[p-1]].x-Q[s[p]].x)*(Q[i].y-Q[s[p]].y)>=(Q[i].x-Q[s[p]].x)*(Q[s[p-1]].y-Q[s[p]].y))
			p--;
		s[++p] = i;
		i++;
		//output();
		//system("pause");
	}
}

double cal(int a,int b,int c)
{
	double A, B, C, P;

	A = sqrt((Q[s[a]].x-Q[s[b]].x)*(Q[s[a]].x-Q[s[b]].x)+(Q[s[a]].y-Q[s[b]].y)*(Q[s[a]].y-Q[s[b]].y));
	B = sqrt((Q[s[a]].x-Q[s[c]].x)*(Q[s[a]].x-Q[s[c]].x)+(Q[s[a]].y-Q[s[c]].y)*(Q[s[a]].y-Q[s[c]].y));
	C = sqrt((Q[s[c]].x-Q[s[b]].x)*(Q[s[c]].x-Q[s[b]].x)+(Q[s[c]].y-Q[s[b]].y)*(Q[s[c]].y-Q[s[b]].y));
	P = (A+B+C)/2.0;
	return sqrt(P*(P-A)*(P-B)*(P-C));
}

int input()
{
	long i;
	double S, min, tmp;
	long a, b;
	//FILE *in, *out;

	//in = fopen("in.txt","r");
	//out = fopen("out.txt","w");
	//fscanf(stdin,"%d%d",&n,&L);
	scanf("%ld",&n);
	if(!n)
		return 0;
	low = 0;
	for(i = 0; i < n; i++)
	{
		fscanf(stdin,"%lf%lf",&Q[i].x,&Q[i].y);
		if(i)
		{
			if(Q[i].y < Q[low].y||(Q[i].y == Q[low].y&&Q[i].x<Q[low].x))
				low = i;
		}
	}
	lowx = Q[low].x; lowy = Q[low].y;
	sort(Q,Q+n,cmp);
	GRAHAM_SCAN();
	//for(i = 0; i < n; i++)
	//	fprintf(out,"%d %d\n",Q[i].x,Q[i].y);
	//fclose(in);
	//fclose(out);
	S = 0;min = 21000000000;
	//printf("%d\n",p);
	for(i = 0; i <= p; i++)
		S += -0.5*(double)(Q[s[i]].x * Q[s[(i+1)%(p+1)]].y - Q[s[i]].y*Q[s[(i+1)%(p+1)]].x);
	if(S<0)
		S *= -1;
	//printf("%lf\n",S);
	for(i = 0; i <= p; i++)
	{
		a = i-1;b = i+1;
		if(a<0)
			a = p;
		if(b==p+1)
			b = 0;
		if((tmp=S-cal(a,i,b))<min)
			min = tmp;
	}
	printf("%.2lf\n",min);
	return 1;
}

int main()
{
	while(input());
	return 1;
}

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