1943674_ac_0ms_60k.c

北大大牛代码 1240道题的原代码 超级权威

# include <stdio.h>

long T(int n)
{
	return n*(n+1)/2;
}
int main()
{
	int i, j, n, N;
	long sum;

	scanf("%d",&n);
	for(i = 1; i <= n; i++)
	{
		scanf("%d",&N);
		sum = 0;
		for(j = 1; j <= N; j++)
			sum += j*T(j+1);
		printf("%d %d %ld\n",i,N,sum);
	}
	return 1;
}