2121069_ac_15ms_48k.c

北大大牛代码 1240道题的原代码 超级权威

# include <stdio.h>

int is_leap(int year)
{
	return ((year%4==0&&year%100!=0)||year%400==0);
}

static int monthdays[] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
static char days[][10] = {"monday","tuesday","wednesday","thursday","friday","saturday","sunday"};

int main()
{
	int year, month, day;
	int t, m, y;

	scanf("%d%d%d",&year,&month,&day);
	t = 0;
	if(year<1900)
	{
    	t += monthdays[month]-day;
    	if(month==2)
    		t += is_leap(year);
     	t%=7;
    	for(m = month+1; m <13; m++)
		{
      	    t+=monthdays[m];
    		if(m==2)
	    		t+=is_leap(year);
	    	t%=7;
		}
		year++;
		for(;year<1900;year++)
		{
			t+=365+is_leap(year);
			t%=7;
		}
		printf("%s\n",days[6-t]);
	}
	else
	{
		t += day-1;
		for(m = 1; m < month; m++)
		{
			t += monthdays[m];
			if(m==2)
				t += is_leap(year);
			t%=7;
		}
		for(y = 1900; y < year; y++)
		{
			t+=365+is_leap(y);
			t%=7;
		}
		printf("%s\n",days[t]);
	}
	return 1;
}