qam_16.asv

PDCCH的实现过程及其遇见的问题应该遇见的问题

function [d_symb]=QAM_16(numbits,d)  %16_QAM调制
numbits=168;
% i=1:numbits;
% b(i)=randn(1,numbits)<0.5;

for n=1:4:numbits
    if d(n)==0&d(n+1)==0&d(n+2)==0&d(n+3)==0 
         Re=1/sqrt(10); 
         Im=1/sqrt(10);
%         select=1;
    elseif d(n)==0&d(n+1)==0&d(n+2)==0&d(n+3)==1
         Re=1/sqrt(10); 
         Im=3/sqrt(10);
%         select=2;
    elseif d(n)==0&d(n+1)==0&d(n+2)==1&d(n+3)==0
        Re=3/sqrt(10); 
        Im=1/sqrt(10);
%         select=3;
    elseif d(n)==0&d(n+1)==0&d(n+2)==1&d(n+3)==1
        Re=3/sqrt(10); 
          Im=3/sqrt(10);
%         select=4;
    elseif d(n)==0&d(n+1)==1&d(n+2)==0&d(n+3)==0 
%         select=5;
    elseif d(n)==0&d(n+1)==1&d(n+2)==0&d(n+3)==1 
%         select=6;
    elseif d(n)==0&d(n+1)==1&d(n+2)==1&d(n+3)==0 
%         select=7;
    elseif d(n)==0&d(n+1)==1&d(n+2)==1&d(n+3)==1 
%         select=8;
    elseif d(n)==1&d(n+1)==0&d(n+2)==0&d(n+3)==0 
%         select=9;
    elseif d(n)==1&d(n+1)==0&d(n+2)==0&d(n+3)==1 
%         select=10;
    elseif d(n)==1&d(n+1)==0&d(n+2)==1&d(n+3)==0 
%         select=11;
    elseif d(n)==1&d(n+1)==0&d(n+2)==1&d(n+3)==1 
%         select=12;
    elseif d(n)==1&d(n+1)==1&d(n+2)==0&d(n+3)==0 
%         select=13;
    elseif d(n)==1&d(n+1)==1&d(n+2)==0&d(n+3)==1 
%         select=14;
    elseif d(n)==1&d(n+1)==1&d(n+2)==1&d(n+3)==0 
%         select=15;
    else d(n)==1&d(n+1)==1&d(n+2)==1&d(n+3)==1 
%         select=16;
    end
    switch select  
        case 1
          Re=1/sqrt(10); 
          Im=1/sqrt(10);
        case 2
          Re=1/sqrt(10); 
          Im=3/sqrt(10);
        case 3
          Re=3/sqrt(10); 
          Im=1/sqrt(10);
        case 4
          Re=3/sqrt(10); 
          Im=3/sqrt(10);
        case 5
          Re=1/sqrt(10); 
          Im=-1/sqrt(10);
        case 6
          Re=1/sqrt(10); 
          Im=-3/sqrt(10);
         case 7
           Re=3/sqrt(10); 
           Im=-1/sqrt(10);
         case 8
           Re=3/sqrt(10); 
           Im=-3/sqrt(10);
         case 9
           Re=-1/sqrt(10); 
           Im=1/sqrt(10);
         case 10
            Re=-1/sqrt(10); 
            Im=3/sqrt(10);
         case 11
            Re=-3/sqrt(10); 
            Im=1/sqrt(10);
         case 12
            Re=-3/sqrt(10); 
            Im=3/sqrt(10);
         case 13
            Re=-1/sqrt(10); 
            Im=-1/sqrt(10);
          case 14
            Re=-1/sqrt(10); 
            Im=-3/sqrt(10);
          case 15
            Re=-3/sqrt(10); 
            Im=-1/sqrt(10);
           case 16
            Re=-3/sqrt(10); 
            Im=-3/sqrt(10);
 end
 for n=1:(numbits/4)
     d_symb(n)=Re+j*Im;
 end
end