ecmf_d.m

计量工具箱

% PURPOSE: demonstrate the use of ecmf
%          function to forecast an error
%          correction model 
% ---------------------------------------------
% usage: ecmf_d
% ----------------------------------------------

clear all;
dates = cal(1982,1,12);
load test.dat; % a test data set containing
               % monthly mining employment for
               % il,in,ky,mi,oh,pa,tn,wv
% data covers 1982,1 to 1996,5

vnames =  ['  il',
           '  in',    
           '  ky',    
           '  mi',    
           '  oh',    
           '  pa',    
           '  tn',    
           '  wv'];    
     

y = test;
[nobs neqs] = size(y);
        
nlag = 9;

nfor = 12; % number of forecast periods
begf = ical(1995,6,dates); % begin forecast in 1995,6
endf = ical(1996,5,dates); % end forecast in 1996,5

actual = y(begf:begf+nfor-1,:);

fprintf(1,'actual levels of mining employment \n');
for i=1:nfor
fprintf(1,'%12s ',tsdate(1982,1,12,begf+i-1));
for j=1:neqs;
fprintf(1,'%8.2f ',actual(i,j));
end;
fprintf(1,'\n');
end;

% determines # of co-integrating relations automatically
fcasts = ecmf(y,nlag,nfor,begf);

fprintf(1,'ECM model with co-integrating relations  \n');
fprintf(1,'automatically determined \n');
fprintf(1,'levels forecast of mining employment \n');
for i=1:nfor
fprintf(1,'%12s ',tsdate(1982,1,12,begf+i-1));
for j=1:neqs;
fprintf(1,'%8.2f ',fcasts(i,j));
end;
fprintf(1,'\n');
end;

% force the use of only 1 co-integrating relation
fcasts = ecmf(y,nlag,nfor,begf,1);

fprintf(1,'ECM model with only 1 co-integrating relation  \n');
fprintf(1,'levels forecast of mining employment \n');
for i=1:nfor
fprintf(1,'%12s ',tsdate(1982,1,12,begf+i-1));
for j=1:neqs;
fprintf(1,'%8.2f ',fcasts(i,j));
end;
fprintf(1,'\n');
end;

% future forecast
begf = nobs+1;
fcasts = ecmf(y,nlag,nfor,begf);

fprintf(1,'ECM model co-integrating relations automatically determined  \n');
fprintf(1,'FUTURE levels forecast of mining employment \n');
for i=1:nfor
fprintf(1,'%12s ',tsdate(1982,1,12,begf+i-1));
for j=1:neqs;
fprintf(1,'%8.2f ',fcasts(i,j));
end;
fprintf(1,'\n');
end;