📄 invint.m
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%% Inverse Polynomial Interpolation%clear;n = 5;x = -1:2/(n-1):1;for i = 1:n f(i) = 1-exp(x(i)^2);endz = [ 0 ];p = AitkenNeville( f, x, z );clear;a = 1.6;b = 2.1;for n = 2:2:6 h = (b-a)/(n-1); x = (a:h:b); f = cos(x).*cosh(x)+ones(size(x)); z = [ 0 ]; p = AitkenNeville( f, x, z );end
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