📄 forbacksub.m
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function [x] = forbacksub(b,LUin,indx)
%
% Solve Ax = b, where A has been factored as PA = LU
%
% function [x] = forbacksub(b,LUin,indx)
% Copyright 1999 by Todd K. Moon
n = length(indx);
% Step 1: solve Ly = Pb
y(1) = b(indx(1));
for k=2:n
y(k) = b(indx(k)) - LUin(k,1:k-1)*y(1:k-1)';
end
% step 2: solve Ux = y
x(n) = y(n)/LUin(n,n);
for j=n-1:-1:1
x(j) = 1/LUin(j,j)*(y(j) - LUin(j,j+1:n)*x(j+1:n)');
end
x = x(:);
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