mixed.c~

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/* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
 * Description: mixed.c qustion3                                               *
 *                                                                             *
 * Written by Suiliang Qiu(Student ID=z3267009) for COMP9021                   *
 * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * */

#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <math.h>
bool check_digit(int*,int*);
int main(void)
{
    for (int m = 1230; m < 9876; ++m)
        {
            int m1=m / 1000;/*T*/
            int m2=m / 100 % 10;/*H*/
            int m3=m / 10 % 10;/*I*/
            int m4=m % 10;/*S*/
            if (m1*m2*m3==0)
                continue;
            int my_bits1=0;
            if (check_digit(&m1,&my_bits1))
                continue;
            if (check_digit(&m2,&my_bits1))
                continue;
            if (check_digit(&m3,&my_bits1))
                continue;
            if (check_digit(&m4,&my_bits1))
                continue;
            int n= m % 100;
            int n1= m3;/*I*/
            int n2= m4;/*S*/
            for (int p1 = 12300; p1 < 99877 ; ++p1)
                {
                    if (p1!=(m*m4))
                        continue;
                    int p11=p1 /10000;
                    int p12=p1 /1000 %10;
                    int p13=p1 /100 %10;/*T*/
                    int p14=p1 /10 %10;/*O*/
                    int p15=p1 %10;/*O*/
                    if (p11==0)
                        continue;
                    if (p12==0)
                        continue;
                    if (p13!=m1)
                        continue;
                    if (p14!=p15)
                        continue;
                    int my_bits2=my_bits1;
                    if(check_digit(&p14,&my_bits2))
                        continue;
                    for (int p2 = 10234; p2 < 98765;++p2)
                        {
                            if (p2!=(m*n1))
                                continue;
                            int p21=p2 /10000;/*H*/
                            int p22=p2 /1000 %10;/*A*/
                            int p23=p2 /100 %10;/*R*/
                            int p24=p2 /10 %10;/*D*/
                            int p25=p2 %10;
                            if (p21!=m2)
                                continue;
                            if (p25==0)
                                continue;
                            int my_bits3=my_bits2;
                            if(check_digit(&p22,&my_bits3))
                                continue;
                            if(check_digit(&p23,&my_bits3))
                                continue;
                            if(check_digit(&p24,&my_bits3))
                                continue;
                            for(int result=123456; result <987654; ++result)
                                {
                                    if (result!=p1+(p2*10))
                                        continue;
                                    int r1= result / 100000;
                                    int r2= result / 10000 % 10;
                                    int r3= result / 1000 % 10;
                                    int r4= result / 100 % 10;
                                    int r5= result / 10 % 10;
                                    int r6= result %10;
                                    if (r1*r2*r3*r4*r5*r6==0)
                                        continue;
                                    printf("%d x %d = %d, with %d,%d as partial products, is a solution.\n",m,n,result,p1,p2);
                                }
                            
                        }
                }
        }
}
bool check_digit(int* x,int* digit)
{
    if((*digit >>*x) % 2 == 0)
        {
            *digit += 1<<*x;
            return false;
        }
    else
        return true;
}