admincheck.java
来自「这个网上商城系统项目是我之前发过类似的一个大的整合」· Java 代码 · 共 58 行
JAVA
58 行
package servlet;
import java.io.IOException;
import java.io.PrintWriter;
import javabean.Admin;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
import dao.RegisterDAO;
public class AdminCheck extends HttpServlet {
/*
* 判断管理员用户登陆成功与否
*/
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
request.setCharacterEncoding("gbk");
response.setContentType("text/html;charset=gbk");
PrintWriter out = response.getWriter();
HttpSession session = request.getSession();
String adminuserName = request.getParameter("userName");
String adminpassWord = request.getParameter("passWord");
RegisterDAO dao = new RegisterDAO();
String sql = "select count(*) from admin where adminuserName=? and adminpassWord=?";
int n = dao.CheckAdmin(sql, adminuserName,adminpassWord);
if(n > 0){
//有相同的表示查询到的用户名和密码正确成功,我想设置权限,根据一个字段类型,由用户名我可以找到id
session.setAttribute("admin", adminuserName);
Admin admin = dao.QueryAdmin(adminuserName);
int adminType = admin.getAdminType();
//通过类型来判断权限
session.setAttribute("adminType", adminType);
response.sendRedirect("/EShopping/Admin/adminIndex.jsp");
} else {
//不相同表示用户名或者密码错误
out.write("<script type='text/javascript'>alert('用户名或密码错误,登录失败,请重新登录!');</script>");
request.getRequestDispatcher("/Admin/adminLogin.jsp").include(request, response);
}
//将处理结果返回给客户端
out.flush();
out.close();
}
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
this.doGet(request, response);
}
}
⌨️ 快捷键说明
复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?